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andrezito [222]
3 years ago
8

PLEASE I NEED HELP ASAP!!!!!!

Mathematics
1 answer:
mixer [17]3 years ago
5 0
Unpaid balance
205.84−25
=180.84
finance charge
180.84×0.015
=2.71
Purchase
98.42−18.63
=79.79

New balance
180.84+2.71+79.79
=263.34

Hope it helps
You might be interested in
a circle is divided into 18 equal parts how many degrees is the angle for each part? how many degrees is the angle for 5 parts?
Ket [755]
There are 360 degrees in a circle, and we have 18 pieces, so we need to see how many times 18 goes into 360. We can find this out by dividing.

360/18=20

You can check this by multiplying 20 and 18 (it equals 360)!

So, each fraction of the circle will be 20 degrees.

If you take 5 of these 20 degree pieces, you'll need to multiply them by 20 to see how many degrees they'd be.

You need to multiply by 20 because each piece is 20 degrees, and we need to find how many degrees 5 pieces is. It's the same as doing
20+20+20+20+20! :)

20*5=100. 5 parts will be 100 degrees.


Hope I helped! :)
4 0
3 years ago
In an examination of purchasing patterns of shoppers, a sample of 16 shoppers revealed that they spent, on average, $54 per hour
Lesechka [4]

Answer:

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X=54 represent the sample mean  

\mu population mean (variable of interest)

\sigma=21 represent the sample standard deviation

n=16 represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.90 or 90%, the value of \alpha=1-0.9=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.05,0,1)".And we see that z_{\alpha/2}=1.64

Now we have everything in order to replace into formula (1):

54-1.64\frac{21}{\sqrt{16}}=45.39    

54 +1.64\frac{21}{\sqrt{16}}=62.61    

So on this case the 90% confidence interval would be given by (45.39;62.61)    

4 0
3 years ago
What is the nonpermissible value of x in 5x/6x+3
cestrela7 [59]

Answer: -\frac{1}{2}

<u>Step-by-step explanation:</u>

\frac{5x}{6x+3}

Restriction: 6x + 3 ≠ 0     <em>denominator cannot be zero</em>

                   <u>     -3  </u>  <u> -3 </u>

                    6x      ≠ -3

                 <u> ÷6       </u>   <u>÷6 </u>

                      x       ≠ -\frac{1}{2}

4 0
3 years ago
Please help me it’s due today! The one on the top is just helping explain the bottom questions
Vinvika [58]

Answer:

dont know

Step-by-step explanation:

3 0
2 years ago
PLEASE DONT AWNSER ANYTHING RANDOM I REALLY NEED THIS AND DO YOUR OWN AWNSER
baherus [9]

Answer:

Fifty percent of the data values lies between 34 and 46.

It is unlikely that there are any outliers.

Step-by-step explanation:

drawing out this box plot and looking online for a picture of the same plot:

From the box plot:

median=46

Q1=42

Q3=70

Q3-Q1= IQR=70-42=28

max=76

min=34

Range=max-min=76-34=42

no outliers seen from boxplot

7 0
2 years ago
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