Help help help im stuck...

Need help with this

cupoosta [38]

a²+b² = c² where a and b are legs and c is the hypotenuse

So...

a²+4²=13²

a²+16=169

a²=153

a=√153

answer: approx. 12.37 units

7 0

3 years ago

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The Malcolms are taking a trip. Midville is 214 miles

Juliette [100K]

Answer:

642 miles

Step-by-step explanation:

Distance of Midville from their home = 214 miles

Walesburg is 3 times as far.

How far is Walesburg from their home?

Distance of Walesburg from their home = 3 × Distance of Midville from their home

= 3 × 214 miles

= 642 miles

Distance of Walesburg from their home = 642 miles

8 0

3 years ago

What is the equation of the line passing through the points (4, -7.5) and (6, -3.5) in slope-intercept form?

Ratling [72]

Answer:

Your answer will be

y=2x-15.5

Step-by-step explanation:

Hi, there you must know the slope-intercept form which is

y=mx+b

m=slope

b=y-intercept

You can also use

the slope formula which is

$\frac{y_2-y_1}{x_2-x_1}$

in this case

it will look like this

$\frac{-7.5-(-3.5)}{6-4}$ = $\frac{-4}{2}$ =-2

So the slope is -2

Now we will find the y-intercept

-7.5=2(4)+b

-7.5=8+b Subtract 8 both sides

-15.5=b

Your y-intercept is -15.5

Hope this helps

6 0

3 years ago

The diagram shows a vertical tower DC on a horizontal ground ABC.

sasho [114]

The measure of ABD=180°- 54°=26°
and then the measure of ADB= x
and x + 26° + 28°= 180°, sum of anlgle in a triagle property
it means x= 180°- 26-28=126°
application of sinus law in the triangle

sin 28 / BD = sin 126/ AD = sin 26/ 25 so we can deduce that

AD= 25sin126 / sin26= 46.12
let 's consider the triangle ADC, so for finding h, we have sin 28 = h / AD
and then h = AD x sin28=21.65

Calculate the height of the tower is 21.65

6 0

3 years ago

Implicit differentiation Please help

Anvisha [2.4K]

Answer:

$y''(-1) =8$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Algebra I

Factoring

Calculus

Implicit Differentiation

The derivative of a constant is equal to 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Chain Rule: $\frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

Quotient Rule: $\frac{d}{dx} [\frac{f(x)}{g(x)} ]=\frac{g(x)f'(x)-g'(x)f(x)}{g^2(x)}$

Step-by-step explanation:

Step 1: Define

-xy - 2y = -4

Rate of change of the tangent line at point (-1, 4)

Step 2: Differentiate Pt. 1

Find 1st Derivative

Implicit Differentiation [Product Rule/Basic Power Rule]: $-y - xy' - 2y' = 0$
[Algebra] Isolate y' terms: $-xy' - 2y' = y$
[Algebra] Factor y': $y'(-x - 2) = y$
[Algebra] Isolate y': $y' = \frac{y}{-x-2}$
[Algebra] Rewrite: $y' = \frac{-y}{x+2}$

Step 3: Find y

Define equation: $-xy - 2y = -4$
Factor y: $y(-x - 2) = -4$
Isolate y: $y = \frac{-4}{-x-2}$
Simplify: $y = \frac{4}{x+2}$

Step 4: Rewrite 1st Derivative

[Algebra] Substitute in y: $y' = \frac{-\frac{4}{x+2} }{x+2}$
[Algebra] Simplify: $y' = \frac{-4}{(x+2)^2}$

Step 5: Differentiate Pt. 2

Find 2nd Derivative

Differentiate [Quotient Rule/Basic Power Rule]: $y'' = \frac{0(x+2)^2 - 8 \cdot 2(x + 2) \cdot 1}{[(x + 2)^2]^2}$
[Derivative] Simplify: $y'' = \frac{8}{(x+2)^3}$

Step 6: Find Slope at Given Point

[Algebra] Substitute in x: $y''(-1) = \frac{8}{(-1+2)^3}$
[Algebra] Evaluate: $y''(-1) =8$

6 0

3 years ago

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