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An athletic field is a 60 yd60 yd-by-120 yd120 yd rectangle, with a semicircle at each of the short sides. A running track 101

gregori [183]

Distance of each track are:

D₁ = 428.5 yd

D₂ = 436.35 yd

D₃ = 444.20 yd

D₄ = 452.05 yd

D₅ = 459.91 yd

D₆ = 467.76 yd

D₇ = 475.61 yd

D₈ = 483.47 yd

Explanation:

Given:

Track is divided into 8 lanes.

The length around each track is the two lengths of the rectangle plus the two lengths of the semi-circle with varying diameters.

Thus,

$D = 2(120) + 2. \frac{1}{2} \pi d\\\\D = 240 + \pi d$

Starting from the innermost edge with a diameter of 60yd.

Each lane is 10/8 = 1.25yd

So, the diameter increases by 2(1.25) = 2.5 yd each lane going outward.

So, the distances are:

D₁ = 240 + π (60) → 428.5yd

D₂ = 240 + π(60 + 2.5) → 436.35 yd

D₃ = 240 + π(60 + 5) → 444.20 yd

D₄ = 240 + π(60 + 7.5) → 452.05 yd

D₅ = 240 + π(60 + 10) → 459.91 yd

D₆ = 24 + π(60 + 12.5) → 467.76 yd

D₇ = 240 + π(60 + 15) → 475.61 yd

D₈ = 240 + π(60 + 17.5) → 483.47 yd

4 0

4 years ago

Balance the following redox reaction by ion electron method. I2+ HNO3 = HI03+ NO2+ H20

Ad libitum [116K]

Answer:

BRO I DONT KNOW SORY I NEED POINTS

Step-by-step explanation:

7 0

3 years ago

Which statement regarding the diagram is true?

Sergeu [11.5K]

Answer

m∠WXY + m∠YXZ = 180°

7 0

4 years ago

Read 2 more answers

Describe the possible lengths of the third side of the triangle given that the lengths of the other two sides are 12 feet and 18

Gennadij [26K]

Answer:

6 ft < L₃ < 30 ft

Step-by-step explanation:

To obtain the answer to the question given above, we must bear in mind that:

The sum of the length of two sides of any triangle is always greater than the 3rd length i.e

L₁ + L₂ > L₃

With the above information in mind, we can obtain the answer to the question given above as follow:

Length 1 (L₁) = 12 feet

Length 2 (L₂) = 18 feet

Length 3 (L₃) =..?

Case 1:

L₁ + L₂ > L₃

12 + 18 > L₃

30 > L₃

L₃ < 30 feet

Case 2:

L₁ + L₃ > L₂

12 + L₃ > 18

Collect like terms

L₃ > 18 – 12

L₃ > 6 feet

Thus,

6 feet < L₃

Combining case 1 and 2,we obtained:

6 ft < L₃ < 30 ft

Therefore, the possible Lenght of the 3rd side is : 6 ft < L₃ < 30 ft

8 0

3 years ago

Can you help me find the answer for slope

pav-90 [236]

Step-by-step explanation:

How you find the slope of a straight line, depends on what information you are given. Here are some pieces of information you might be given and how to find the slope in each:

two random points

* Use the formula for slope and substitute each of the x and y values.

$slope = m = \frac{{y_2}-y_{1}}{x_{2}-x_{1}}$

Ex: given points (1,2) and (3,4)

$m = \frac{{y_2}-y_{1}}{x_{2}-x_{1}}$

$m = \frac{4-2}{3-1}$

$m = \frac{2}{2}$

$m = 1$

picture of the graph

* You can choose two random points on the graph and do two random points method

* OR you can use another formula for slope: m = rise/run

First, choose two random points on the graph that are on the grid lines. Count distance between first and second point. (The first point being on the left side.)

- Count how far away the two points are vertically. This number is "rise". If the second point is under the first point, the rise is a negative number.

- Count how far away they are horizontally. This is the "run". This number will not be negative.

Divide the number for rise by the number for run to get the slope.

random point and the y-intercept

* Use slope-intercept form and substitute the random point and the y-intercept

y = mx + b

Substitute the y-coordinate of the point for y, the x-coordinate of the point for x, and the y-intercept for b.

Isolate m to find the slope.

Ex: given (2,1) and y-intercept (0, 0)

y = mx + b

1 = m2 + 0

1 = 2m

m = 1/2

6 0

4 years ago