All categories

2 years ago

How to find the average rate of change of a function

Mathematics

1 answer:

ollegr [7]2 years ago

5 0

ANSWER

Average Rate of Change

$= \frac{f(b) - f(a)}{b - a}$

EXPLANATION

To find the average rate of change of y=f(x) from x=a to x=b means finding the slope of the secant line joining the points

(a,f(a)) and (b,f(b))

The slope of the secant line joining these points is

$= \frac{f(b) - f(a)}{b - a}$

This gives the average rate of change of the function.

You might be interested in

Calculate the interest Greg will pay on this loan.

Alina [70]

Answer:

that is the solution to the question

8 0

2 years ago

an outlier may be defined as a data point that is more than 1.5 times the interquartile range below the lower quartile or is mor

Ira Lisetskai [31]

Supposing a normal distribution, we find that:

The diameter of the smallest tree that is an outlier is of 16.36 inches.

--------------------------------

We suppose that tree diameters are normally distributed with mean 8.8 inches and standard deviation 2.8 inches.

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean.
After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem:

Mean of 8.8 inches, thus $\mu = 8.8$ .
Standard deviation of 2.8 inches, thus $\sigma = 2.8$ .

The interquartile range(IQR) is the difference between the 75th and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = -0.675(2.8)$

$X = 6.91$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 8.8}{2.8}$

$X - 8.8 = 0.675(2.8)$

$X = 10.69$

The IQR is:

$IQR = 10.69 - 6.91 = 3.78$

What is the diameter, in inches, of the smallest tree that is an outlier?

The diameter is 1.5IQR above the 75th percentile, thus:

$10.69 + 1.5(3.78) = 16.36$

The diameter of the smallest tree that is an outlier is of 16.36 inches.

A similar problem is given at brainly.com/question/15683591

3 0

2 years ago

For triangle ABC, find the measure of AB given me∠ A = 55 degrees, m∠b= 44 degrees, and b=6. . A. 45.22. B.96.68. C.88.19. .

jekas [21]

There exist a similar question where b = 68 instead of 6. First, determine the measure of the third angle, angle C,
m∠c = 180 - (55° + 44°) = 81°
Let x be the side AB, that which is opposite to angle C. Through the Sine Law,
68 / sin 44° = x / sin 81°
From the equation, the value of x is equal to 96.68. Thus, the answer is letter B.

4 0

3 years ago

Read 2 more answers

A scientist is studying the characteristics of butterflies and collects a random sample of butterflies to measure. Information r

Alchen [17]

Answer:

I believe it's C. Wingspan is a continuous quantitative variable.

6 0

2 years ago

Read 2 more answers

A density curve for all the possible temperatures between 0°F and 40°F is a

My name is Ann [436]