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just olya [345]
2 years ago
6

A Herbig-Haro (HH) object is:_:_________.

Chemistry
1 answer:
Phoenix [80]2 years ago
5 0

Given what we know about Herbig-Haro (HH) objects, we can confirm that they are born from the collision between a jet from a star and clouds of interstellar matter.

<h3>What are Herbig-Haro (HH) objects?</h3>
  • To put it simply, a Herbig-Haro (HH) object is what we observe as a bright spot in distant space. Upon closer observation we can observe that these giant bright patches are not lone objects, but in fact immense groups of interstellar matter.

<h3>How Herbig-Haro (HH) objects are formed.</h3>
  • The formation of one of these interstellar groups requires an <em><u>immense amount of energy</u></em>. This energy come from the speed at which the materials that form these objects collide.
  • As stated in the question, the jet released from a star in the process of being born <em><u>smashes into a giant cloud of </u></em><em><u>dust </u></em><em><u>and </u></em><em><u>interstellar material </u></em><em><u>to form the </u></em><em><u>Herbig</u></em><em><u>-</u></em><em><u>Haro </u></em><em><u>(HH) </u></em><em><u>objects</u></em>.
  • This collision happens at hundreds of km/s. To put it into perspective, it would be roughly 500,000 miles per hour.

Therefore, we can confirm that option b, which states, "<em>where a jet from a </em><em>star </em><em>in the process of being born </em><em>collides </em><em>with (and lights up) a nearby cloud of </em><em>interstellar matter</em>", is the correct choice for the question pertaining to Herbig-Haro (HH) objects.

To learn more about interstellar space visit:

brainly.com/question/7106246

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Lelu [443]
<h2>Hello!</h2>

The answer is: The new pressure is 1.67 atm.

<h2>Why?</h2>

From the statement, we know that the temperature remains constant and the gas volume is changing, meaning that the new pressure will be different than the first pressure.

Since the temperature remains constant, we can calculate the new pressure using the Boyle's Law.

The Boyle's Law states that:

P_{1}V_{1}=P_{2}V_{2}

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P is the pressure of the gas.

V is the volume of the gas.

Then, the given information is:

V_{1}=125ml=0.125L\\P_{1}=1atm\\V_{2}=75ml=0.075L

Remember, 1 L is equal to 1000 mL.

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125mL*\frac{1L}{1000mL}=\frac{125mL*1L}{1000mL}=0.125L\\\\75mL*\frac{1L}{1000mL}=\frac{75mL*1L}{1000mL}=0.075L

So, calculating the new volume, we have:

P_{1}V_{1}=P_{2}V_{2}\\\\1atm*0.125L=P_{2}*0.075L\\\\P_{2}=\frac{1atm*0.125L}{0.075l}=1.67atm

Hence, the new pressure is 1.67 atm.

Have a nice day!

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