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KATRIN_1 [288]
4 years ago
10

What does it mean foe a hypothesis to be testialbe

Chemistry
1 answer:
marin [14]4 years ago
5 0

Answer:

For a hypothesis to be testable means that is it possible to make observations that agree or disagree with it. This statement may or may not be true, but it is not a scientific hypothesis. That's because it can't be tested.

Explanation:

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a store receives a shipment of defective balloons. each has a tiny pinhole of the same size. if one balloon is filled with heliu
densk [106]
YOu should use the Graham's Law of Diffusion

R1/ R2 = √(M2/ M1)  

Helium is R1, air is R2.

I'm not sure if your professor gives density or molar mass for this problem? You need M2 and M1 to solve for the rates of diffusion. 




8 0
4 years ago
What is the molarity of HCl found in a titration where 50 ml of HCl is titrated with 50 ml of .1 M NaOH? Needs to be answered as
Aneli [31]

0.1 mol/L . The concentration of the HCl is 0.1 mol/L

a) Write the <em>balanced chemical equation </em>

HCl + NaOH → NaCl + H2O

b) Calculate the <em>moles of NaOH </em>

Moles of NaOH = 0.050 L NaOH x (0.1 mol NaOH/1 L NaOH)

= 0.0050 mol NaOH

c) Calculate the <em>moles of HCl </em>

Moles of HCl = 0.0050 mol NaOH x (1 mol HCl/1 mol NaOH)

= 0.0050 mol HCl

d) Calculate the <em>molar concentration</em> of the HCl

<em>c</em> = moles/litres = 0.0050 mol/0.050 L = 0.1 mol/L

7 0
4 years ago
How we can measure the density of different wooden object?
Novay_Z [31]
Seeing how much of the object can take with an amount of pressure
5 0
4 years ago
Calculate the percent yield of a reaction where a student collected 16.8 grams of product and was expecting to collect 49.7 gram
masya89 [10]

Answer:

\boxed{\text{33.8 \%}}

Explanation:

\text{\% yield} = \dfrac{\text{actual yield}}{\text {theoretical yield}} \times\text{100 \%}

Data:

        Actual yield = 16.8 g

Theoretical yield = 49.7 g

Calculation:

\text{\% yield} = \dfrac{\text{16.8 g}}{\text {49.7 g}} \times\text{100 \%} = \boxed{\textbf{33.8 \%}}

8 0
3 years ago
An equilibrium mixture contains 0.750 mol of each of the products (carbon dioxide and hydrogen gas) and 0.200 mol of each of the
sasho [114]

1.302  moles of carbon dioxide would have to be added

<h3>Further explanation</h3>

The equilibrium constant is the value of the product in the equilibrium state of the substance in the right (product) divided by the substance in the left (reactant) with the exponents of each reaction coefficient

The equilibrium constant is based on the concentration (Kc) in a reaction

pA + qB -----> mC + nD

\large {\boxed {\bold {Kc ~ = ~ \frac {[C] ^ m [D] ^ n} {[A] ^ p [B] ^ q}}}}

While the equilibrium constant is based on partial pressure

\large {\boxed {\bold {Kp ~ = ~ \frac {[pC] ^ m [pD] ^ n} {[pA] ^ p [pB] ^ q}}}}

The value of Kp and Kc can be linked to the formula '

\large {\boxed {\bold {Kp ~ = ~ Kc. (R.T) ^ {\Delta n}}}}

R = gas constant = 0.0821 L.atm / mol.K

=n = number of product coefficients-number of reactant coefficients

An equilibrium mixture: 0.750 moles of CO2 and H2, and 0.200 moles of CO and H2O

  • We determine Kc (constant concentration)

\displaystyle Kc=\frac{0.75.0.75}{0.2.0.2}\\\\Kc=14.1

  • the amount of carbon monoxide to 0.300 mol

Reaction :

                CO +H₂O ⇔ CO₂ + H₂

initially      0.2   0.2       0.75+x  0.75

reaction    0.1    0.1        0.1         0.1

product     0.3   0.3       0.65+x    0.65

\displaystyle Kc=\frac{(0.650+x)(0.65)}{0.3.0.3}\\\\14.1(0.09)=0.4225+0.65x\\\\1.269-0.4225=0.65x\\\\0.8465=0.65x\\\\x=1.302

<h3>Learn more</h3>

an equilibrium constant brainly.com/question/9173805

brainly.com/question/1109930

Calculate the value of the equilibrium constant, Kc

brainly.com/question/3612827

Concentration of hi at equilibrium

brainly.com/question/8962129

Keywords: constant equilibrium, Kc, concentration, product, reactant, reaction coefficient

3 0
4 years ago
Read 2 more answers
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