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3 years ago

1. Generally speaking, where on the periodic table are the elements that form ions requiring!

Chemistry

1 answer:

Artemon [7]3 years ago

7 0

Answer:

The middle, or the transitional metals

Explanation:

When naming elements, we use roman numerals to indicate what their charge is. The charge of an element is affected by their number of valence electrons (outermost electrons).

Transitional metals are generally <u>multivalent</u>, meaning that element has more than one possible number of valence electrons. This makes them have more than one possible charge. Roman numerals indicate which charge of that element is used/discussed.

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You mix 200. mL of 0.400M HCl with 200. mL of 0.400M NaOH in a coffee cup calorimeter. The temperature of the solution goes from

GuDViN [60]

Answer : The enthalpy of neutralization is, 56.012 kJ/mole

Explanation :

First we have to calculate the moles of HCl and NaOH.

$\text{Moles of HCl}=\text{Concentration of HCl}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

$\text{Moles of NaOH}=\text{Concentration of NaOH}\times \text{Volume of solution}=0.400mole/L\times 0.200L=0.08mol$

The balanced chemical reaction will be,

$HCl+NaOH\rightarrow NaCl+H_2O$

From the balanced reaction we conclude that,

As, 1 mole of HCl neutralizes by 1 mole of NaOH

So, 0.08 mole of HCl neutralizes by 0.08 mole of NaOH

Thus, the number of neutralized moles = 0.08 mole

Now we have to calculate the mass of water.

As we know that the density of water is 1 g/ml. So, the mass of water will be:

The volume of water = $200mL+200L=400mL$

$\text{Mass of water}=\text{Density of water}\times \text{Volume of water}=1g/ml\times 400mL=400g$

Now we have to calculate the heat absorbed during the reaction.

$q=m\times c\times (T_{final}-T_{initial})$

where,

q = heat absorbed = ?

$c$ = specific heat of water = $4.18J/g^oC$

m = mass of water = 400 g

$T_{final}$ = final temperature of water = $27.78^oC=273+25.10=300.78K$

$T_{initial}$ = initial temperature of metal = $25.10^oC=273+27.78=298.1K$

Now put all the given values in the above formula, we get:

$q=400g\times 4.18J/g^oC\times (300.78-298.1)K$

$q=4480.96J$

Thus, the heat released during the neutralization = -4480.96 J

Now we have to calculate the enthalpy of neutralization.

$\Delta H=\frac{q}{n}$

where,

$\Delta H$ = enthalpy of neutralization = ?

q = heat released = -4480.96 J

n = number of moles used in neutralization = 0.08 mole

$\Delta H=\frac{-4480.96J}{0.08mole}=-56012J/mole=-56.012kJ/mol$

The negative sign indicate the heat released during the reaction.

Therefore, the enthalpy of neutralization is, 56.012 kJ/mole

8 0

3 years ago

Consider the compound mgcl2 what type of compound does it represent?

Naily [24]

MgCl2 is a ionic compound because it is formed by a metal (Mg) and a non-metal (Cl)

4 0

3 years ago

If a given aqueous solution at 298 K contains [H+] = 1.0 × 10-9, what is the [OH-]?

Zinaida [17]

Answer:

Explanation:

$\frac{1x10}x^{-14} = 1x10^{-9} \\ x =1x10^{-5} \\\\[OH][H]= 1x10^{-14}$

The concetration can be found by dividing the water ph constant by the [H=] or [OH] to find the other

6 0

4 years ago

Suppose the gas packed in a champagne bottle is manipulated such that the total pressure of the gas is 760 mm Hg, with a PCO2 of

Valentin [98]

We expect the release of PCO2 from the bottle, When the cork is pulled.

<h3>What do you expect to happen?</h3>

When the cork is pulled, we expect the release of PCO2 in the atmosphere to happen because there is high concentration of PCO2 in the bottle but there is no concentration of PCO2 in the atmosphere so due to diffusion, the PCO2 gas moves outside the bottle.

So we can conclude that When the cork is pulled, the release of PCO2 from the bottle will be expected.

Learn more about pressure here: brainly.com/question/25736513

#SPJ1

5 0

3 years ago

Liquid sodium is being considered as an engine coolant. How many grams of liquid sodium (minimum) are needed to absorb of energy

umka21 [38]

Answer:

See explanation below

Explanation:

First, you are not providing any data to solve this, so I'm gonna use some that I used a few days ago in the same question. Then, you can go and replace the data you have with the procedure here

The concentration of liquid sodium will be 8.5 MJ of energy, and I will assume that the temperature will not be increased more than 15 °C.

The expression to calculate the amount of energy is:

Q = m * cp * dT

Where: m: moles needed

cp: specific heat of the substance. The cp of liquid sodium reported is 30.8 J/ K mole

Replacing all the data in the above formula, and solving for m we have:

m = Q / cp * dT

dT is the increase of temperature. so 15 ° C is the same change for 15 K.

We also need to know that 1 MJ is 1x10^6 J,

so replacing all data:

m = 8.5 * 1x10^6 J / 30.8 J/K mole * 15 m = 18,398.27 moles

The molar mass of sodium is 22.95 g/mol so the mass is:

mass = 18,398.27 * 22.95 = 422,240.26 g or simply 422 kg rounded.

5 0

4 years ago