Answer:
There are two kinds of forces, or attractions, that operate in a molecule—intramolecular and intermolecular. Let's try to understand this difference through the following example.
Explanation:
We have six towels—three are purple in color, labeled hydrogen and three are pink in color, labeled chlorine. We are given a sewing needle and black thread to sew one hydrogen towel to one chlorine towel. After sewing, we now have three pairs of towels: hydrogen sewed to chlorine. The next step is to attach these three pairs of towels to each other. For this we use Velcro as shown above.
So, the result of this exercise is that we have six towels attached to each other through thread and Velcro. Now if I ask you to pull this assembly from both ends, what do you think will happen? The Velcro junctions will fall apart while the sewed junctions will stay as is. The attachment created by Velcro is much weaker than the attachment created by the thread that we used to sew the pairs of towels together. A slight force applied to either end of the towels can easily bring apart the Velcro junctions without tearing apart the sewed junctions.
Exactly the same situation exists in molecules. Just imagine the towels to be real atoms, such as hydrogen and chlorine. These two atoms are bound to each other through a polar covalent bond—analogous to the thread. Each hydrogen chloride molecule in turn is bonded to the neighboring hydrogen chloride molecule through a dipole-dipole attraction—analogous to Velcro. We’ll talk about dipole-dipole interactions in detail a bit later. The polar covalent bond is much stronger in strength than the dipole-dipole interaction. The former is termed an intramolecular attraction while the latter is termed an intermolecular attraction.
Answer:
when something is boiling. the temperature increases quickly so B and D are eliminated. So its either A or C. My guess is A
Answer:
1121.08 millilitres of 0.223 M
solution contains 0.250 moles of
.
Explanation:
The formula for molarity of a solution:

Molarity = 0.223 M
n = 0.250 moles

Therefore, 1121.08 millilitres of 0.223 M
solution contains 0.250 moles of
.
2M
Explanation:
Given that:
V1 = 50mL
M1 = 40M
V2 = 1000mL
unknown:
M2 = ?
Solution:
Concentration is the number of moles solute in a solution.
Since the number of moles in the solute remains the same;
Concentration = 
number of moles = concentration x volume
Number of moles before and after the dilution remains the same;
M1 x V1 = M2 x V2
M1 is initial concentration
V1 is initial volume
M2 is final concentration
V2 is final volume
40 x 50 = M2 x 1000
M2 = 2M
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Answer:
AgNO3 + NaOH = AgOH + NaNO3.
Explanation:
<em><u>Balancing Strategies: In this reaction, the products are initially NaNO3 + AgOH. However the AgOH would break down into Ag2O and H2O. This would give us NaNO3 + Ag2O + H2O as our products for the overall reaction.</u></em>
<em><u>Balancing Strategies: In this reaction, the products are initially NaNO3 + AgOH. However the AgOH would break down into Ag2O and H2O. This would give us NaNO3 + Ag2O + H2O as our products for the overall reaction.However, the equation balanced here is the initial reaction which produces AgOH and NaNO3.</u></em>