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2 years ago

8. How would you describe kelp? (2 points)

1 answer:

5 0

I think the closest correct answer, based on the given options, is 8. a plant that grows deep in the ocean9. dominant predators, eat other organisms for energy
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For the reaction 2NOCl(g) <-----> 2NO(g) + Cl2(g), Kc = 8.0 at a certain temperature. What concentration of NOCl must be p

Nat2105 [25]

Answer is: concentration of NOCl is 3.52 M.

Balanced chemical reaction: 2NOCl(g) ⇄ 2NO(g) + Cl₂(g).
Kc = 8.0.
[NOCl] = 1.00 M; equilibrium concentration.
[NO] = x.
[Cl₂] = x/2; equilibrium concentration of chlorine.
Kc = [Cl₂] ·[NO]² / [NOCl].
8.00 = x/2 · x² / 1.
x³/2 = 8.
x = ∛16.
x = 2.52 M.
co(NOCl) = [NOCl] + x.
co(NOCl) = 1.00 M + 2.52 M.
co(NOCl) = 3.52 M; the initial concentration of NOCl.

7 0

2 years ago

nignag [31]

Answer:

Explanation:

I think it is D. Think about it- if a human jumps, they are less than the gravitational force. But, if you are greater than the gravitational force, I think you will go into space.

4 0

2 years ago

Determine whether you can swim in 1.00 x 10^27 molecules of water.

zloy xaker [14]

Answer:

We can not swim in 1.00 × 10²⁷ molecules of water

Explanation:

The given number of molecules of water = 1.00 × 10²⁷ molecules

The Avogadro's number, $N_A$ , gives the number of molecules in one mole of a substance

$N_A$ ≈ 6.0221409 × 10²³ molecules/mol

Therefore

Therefore, we have;

The number of moles of water present in 1.00 × 10²⁷ molecules, n = (The number of molecules of water) ÷ $N_A$

∴ n = (1.00 × 10²⁷ molecules)/(6.0221409 × 10²³ molecules/mol) = 1,660.53902857 moles

The mass of one mole of water = The molar mass of water = 18.01528 g/mol

The mass, 'm', of water in 1,660.53902857 moles of water is given as follows;

Mass = (The number of moles of the substance) × (The molar mass of the substance)

∴ The mass of the water in the given quantity of water, m = 1,660.53902857 moles × 18.01528 g/mol ≈ 29.9150756 kg.

The density pf water, ρ = 997 kg/m³

Volume = Mass/Density

∴ The volume of the water present in the given quantity of water, v = 29.9150756 kg/(997 kg/m³) ≈ 30.0050909 liters

The volume of the water present in 1.00 × 10²⁷ molecules of water ≈ 30.0 liters

The average volume of a human body = 62 liters

Therefore, we can not swim in the given quantity of 1.00 × 10²⁷ molecules = 30.0 liters water

7 0

2 years ago

A sample of air has a volume of 140.0 mL at 67C. To w

bonufazy [111]

Answer:

What that means is that when pressure and number of moles are kept constant, increasing the temperature will result in an increase in volume. Likewise, a decrease in temperature will result in a decrease in volume. In your case, the volume of the gas decreased by a factor of about 3, from "140.0 mL" to "50.0 mL".

7 0

2 years ago

What is the mass of 18.0 mL of honey if its' density is 1.42 g/mL?

BigorU [14]

mass (m) = ? , volume = 18.0 ml , density = 1.42 g/ml .

$density = \frac{mass}{volume} \\ \\ d = \frac{m}{v} \\ \\ mass = density \times volume \\ \\ m = d \times v \\ \\ m = 18 \: ml \times \: 1.42 \: \frac{g}{ml} \\ \\ m = 25.56 \: g$

I hope I helped you^_^

8 0

1 year ago