The point (4,y) has a known x coordinate of x = 4. The y coordinate is unknown right now so we'll just call it y.
Draw a vertical line (see side note below) through 4 on the x axis. I've done so in red (see attached image). The red line crosses the graph at the point (4,1) so this tells us that
y = 1Answer: y = 1
Side Note: you don't have to draw a vertical red line but it's handy to see how it works out. After you get used to these types of problems, you can visually be able to see the answer without these extra lines.
Answer:
In words the answer is between t=0 and t=2.
In interval notation the answer is (0,2)
In inequality notation the answer is 0<t<2
Big note: You should make sure the function I use what you meant.
Step-by-step explanation:
I hope the function is h(t)=-16t^2+32t because that is how I'm going to interpret it.
So if we can find when the ball is on the ground or has hit the ground (this is when h=0) then we can find when it is in the air which is between those 2 numbers.
0=-16t^2+32t
0=-16t(t-2)
So at t=0 and t=2
So the ball is in the air between t=0 and t=2
Interval notation (0,2)
Inequality notation 0<t<2
A vertical line on the value x = -4
Answer:
The inverse function is f(x) = x^2 - 3
Step-by-step explanation:
To find the inverse of any function, start by switching the x and f(x) values.
f(x) = √(x + 3)
x = √(f(x) + 3)
Now solve for the new f(x). The result will be your inverse function.
x = √(f(x) + 3)
x^2 = f(x) + 3
x^2 - 3 = f(x)