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Mrac [35]
2 years ago
14

The figure below has a volume of 60 cubic units. How many more cubes will it take to fill the figure?

Mathematics
1 answer:
jolli1 [7]2 years ago
4 0

Answer:

40 cubic units

Step-by-step explanation:

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The shelf is made of 3 pieces of wood, each 0.3 meter wide. There is also 0.05 meter of space between the shelf and the wall on
lutik1710 [3]
Since there are 2 sides to the shelf, there is 0.05*2=0.05+0.05=0.1 meters of space between the shelf and wall in total. Next, since each piece of wood is 0.3 meters wide and we have 3 of them, the total width of the wood is 0.3+0.3+<something>
Note that <width of wood>+<space between shelf and well> =width of closet
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8 0
3 years ago
Please help me with this literal equation!
ollegr [7]

Answer:

x = \frac{n-20}{3a}

Step-by-step explanation:

Given

\frac{3ax-n}{5} = - 4

Multiply both sides by 5

3ax - n = - 20 ( add n to both sides )

3ax = - 20 + n = n - 20

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x = \frac{n-20}{3a}

4 0
3 years ago
Read 2 more answers
How do you solve<br> 25n=70
alisha [4.7K]
You want to do to one side the same thing you do to the other side.

In order to get the n by itself you divide the 25n by 25. But in order to not change the answer you need to do the same to the 70.

\frac{25n}{25} =  \frac{70}{25}

so n=\frac{70}{25} which can be reduced to \frac{14}{5}

so n=\frac{14}{5}
5 0
3 years ago
Find the exact values of sin2 θ for cos θ = 3/18 on the interval 0° ≤ θ ≤ 90°
mote1985 [20]

Answer:

sin(2\theta)=\frac{\sqrt{35} }{18}

Step-by-step explanation:

Recall the formula for the sine of the double angle:

sin(2\theta)=2*sin(\theta)*cos(\theta)

we know that cos(\theta)=\frac{3}{18}, and that \theta is in the interval between 0 and 90 degrees, where both the functions sine and cosine are non-negative numbers. Based on such, we can find using the Pythagorean trigonometric property that relates sine and cosine of the same angle, what sin(\theta) is:

cos^2(\theta)+sin^2(\theta)=1\\sin^2(\theta)=1-cos^2(\theta)\\sin(\theta)=\sqrt{1-cos^2(\theta)} \\sin(\theta)=\sqrt{1-(\frac{3}{18} )^2}\\sin(\theta)=\sqrt{1-\frac{9}{324} }\\sin(\theta)=\sqrt{\frac{324-9}{324} }\\sin(\theta)=\sqrt{\frac{315}{324} }\\\\sin(\theta)=\frac{3}{18}\sqrt{35 }

With this information, we can now complete the value of the sine of the double angle requested:

sin(2\theta)=2*sin(\theta)*cos(\theta)\\sin(2\theta)=2*\frac{3}{18} \,\sqrt{35} \,\frac{3}{18}\\sin(2\theta)=\frac{2*3*3}{18*18}\,\sqrt{35} \\sin(2\theta)=\frac{\sqrt{35} }{18}

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