The calculated pH of the solutions are given below:
- The pH of the solution after 14.0 ml of base is added to it is calculated as 1.45.
- The pH of the solution after 19.8 ml of base is added to it is calculated as 3.0
- The pH of the solution after 20.0 ml of base is added to it is calculated as 7.
<h3>What is pH?</h3>
This is the level of acidity or alkalinity of an aqueous solution. The pH of a substances tells if its an acid, base or neutral.
HBr and NaOH while in water would dissociate and they would become H+ and OH- respectively.
Mol of HBr = Mol * Vol
= 0.200 * 20mL
= 4 mmol
A. Moles of NaOH added
= 0.2 X 14
= 2.8 mmol
Moles of H+ that did not react
= 4 - 2.8
= 1.2 mmol
1.2/1000 = 0.0012 moles
Total volume = 20 + 14
= 34 mL to litres
= 0.034 L
Molarity of H+ = 0.0012 / 0.034L
= 0.035 M
-log[0.035] = 1.45
The pH of the solution is 1.45
B. NaOH added = 19.8 * 0.2 =
3.96 mmoles
The unreacted solution
= 4.0 - 3.96
= 0.04 mmol
0.04/1000 = 0.00004 moles
Total volume = 20 + 19.8
= 39.8mL
Converted to litres = 0.0398L
Molarity = 0.00004 / 0.0398L
= 0.001
-log(0.001) = 3.0
The ph Is therefore 3.0
C. Moles of NaOH added = 0.2*20mL = 4mmol
All the H+ are going to be consumed here. This would result into a neutral solution pH = 7
<u>Complete question:</u>
20.0 mL sample of 0.200 M HBr solution is titrated with 0.200 M NaOH solution. Calculate the PH of the solution after the following volumes of base have been added.
A. 14.0 mL
B. 19.8 mL
C. 20.0 mL
Read more on pH here; brainly.com/question/22390063
The mass of the acetic acid is 1.512 g.
<h3 /><h3>What is Molarity?</h3>
molarity is the concentration of a substance in mol per dm³
From the question,
The number of moles contained in the 30 mL vinegar is
- n = (0.84×30)/1000
- n = 0.0252 mol.
the molar mass of vinegar is calculated below.
- m.m of (HC₂H₃O₂) = [1+(12×2)+(1×3)+(16×2)]
- m.m = (1+24+3+32]
- m.m = 60 g/mol.
To calculate the mass of acetic acid, we use the formula below.
- R.m = n×m.m............. Equation 1
Where
- R.m = mass of acetic acid.
Substitute these values into equation 1
- R.m = (0.0252×60)
- R.m = 1.512 g.
Hence, The mass of the acetic acid is 1.512 g.
Learn more about molarity here: brainly.com/question/20383725
<span> It's locked away in glaciers (in ice).</span>
