It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
1.5326
Step-by-step explanation:
there is no more simplification it can only be calculated by a calculator
Answer:
40
Step-by-step explanation:
(120 - 40)/2 = 80/2 = 40
Answer:
First check your grammar pls I had to read it twice and I think it is 333 5/6
Step-by-step explanation:
Answer:
The independent is the 90 gallons and the dependent is the 8 minutes.
Hope this helps!
Step-by-step explanation:
