The high temperature is 35 degree celsius
<em><u>Solution:</u></em>
Given that, Temperature in degrees Fahrenheit is equal to 32 more than 9/5 times the temperature in degrees Celsius
Let "f" be the temperature in degree Fahrenheit
Let "c" be the temperature in degree celsius
Therefore,
Temperature in degrees Fahrenheit = 32 +
times the temperature in degrees Celsius

One day the high temperature in Edison. Nj was 95 degrees Fahrenheit
f = 95 ; c = ?
Substitute f = 95 in above equation

Thus high temperature in degrees Celsius is 35 degree celsius
Answer: True
Solution:
Rearrange the equation to the LHS:
[x^2 + 8x + 16] · [x^2 – 8x + 16] - (x^2 – 16)^2 = 0
Factoring x^2+8x+16
x^2 - 4x - 4x - 16
= (x-4) • (x-4)
= = (x+4)2
So now we have an equation
(x + 4)^2 • (x - 4)^2 - (x^2 - 16)^2 = 0
Step 2: Evaluate the following:
(x+4)2 = x^2+8x+16
(x-4)2 = x^2-8x+16
(x^2-16)2 = x^4-32x^2+256
(x^2+8x+16) (x^2-8x+16 ) - (x^4-32x^2+256 )
0 = 0
Hence True
22° you just subtract the numbers.