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Dmitry_Shevchenko [17]
2 years ago
10

How much NaNO3 can I dissolve in 400 grams of water at 283 K?

Chemistry
1 answer:
jeyben [28]2 years ago
8 0
929282827280182292848474748393027373882
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exactly 1mol of n2o4 is placed in an empty 1 l container. if at equilibrium n2o4 is dissociated 20%, what is the value of equili
egoroff_w [7]

Answer:

K = 0.2

Explanation:

Based on the chemical dissociation of N₂O₄:

N₂O₄ ⇄ 2NO₂

The equilibrium constant, K, of the reaction is:

K = [NO₂]² / [N₂O₄]

Now, if 20% of N₂O₄ is dissociated, 80% remains as N₂O₄ = 0.8mol/L = 0.8M

as 20% is dissociated, 0.2moles of N₂O₄ were dissociated and 0.2*2 = 0.4mol/L of NO₂ are produced.

Replacing in K:

K = [0.4M]² / [0.8M]

<h3>K = 0.2</h3>
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A cube has sides of 11.4 cm. What is its volume?
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KonstantinChe [14]

Answer:

14.048 moles I believe.

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(8.46 * 10^24) / ( 6.022 * 10^23) = 14.048

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