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Karolina [17]
2 years ago
6

This graph represents a population of molecules in a gas versus the distribution of the average velocity(speed) of its molecules

in that population. Assume all molecules to be of the same mass. In reading the graph, it is important to note three things. One, is the most probable speed is at the peak of the curve. Secondly, the most probable speed increases as the temperature increases (so shift to the right), and the distribution broadens as it increases.
On the graph, indicate the average kinetic energy of the population.

Explain your answer.

What part of the graph indicates the temperature of the sample?

Explain your answer.

Sketch a curve that represents the distribution of molecules at a temperature below the one shown. Label it as T2. Describe both T and T2 in terms of their average kinetic energy. Be specific and detailed.

Submit your answer below.

Chemistry
1 answer:
pshichka [43]2 years ago
3 0

Answer:

Part A

Given that the graph is symmetrical and bell shaped, the average kinetic energy is given by the midline of graph, which corresponds to the common speed of the highest number of the population

Part B

The formula for the average kinetic energy, K.E. = (3/2)·(R/NA)·T

Therefore, the part of the graph that indicates the temperature of the sample is the average kinetic energy. K.E.

Part C

At a lower temperature, the heat is less evenly distributed and we have the distribution T2 higher than T1

Please see the attached graph created with MS Visio

Explanation:

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Answer:

Explanation:

From the statement of the problem,

  B₂S₃_{s} + H₂O_{l}  →  H₃BO₃_{aq} + H₂S_{g}

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We that the above expression does not conform with the law of conservation of mass:

To obey the law, we need to derive a balanced reaction equation:

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let the balanced equation be:

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