Answer:
D
Explanation:
I don't exactly remember his four points, but the D. is just not true anyway. For example, a molecule of water (H20) does that have the same properties or mass as Nitrogen dioxide or sulfer dioxide or something else
Nitrogen dioxide is one of the primary components of air pollution. It is released by the combustion of nitrogen oxide.
<h3 /><h3>How do you calculate the percentage yield of nitrogen oxide?</h3>
Given:
- Mass of nitrogen oxide consumed = 1500 kg
- Mass of nitrogen oxide produced = 1500 kg
The given chemical equation of nitrogen oxide is:
Now, to calculate the percentage yield, the following conversion factor should be used:
Nitrogen dioxide = 2300 kg
The percentage yield will be:
Percentage yield = 65.2 %
Thus, the percentage yield of nitrogen dioxide is 65.2%.
Learn more about <u>percentage yield </u>here:
brainly.com/question/9352001
Answer:
Twice as much.
Explanation:
That's because the freezing point depression depends on the total number of solute particles.
C₆H₁₂O₆(s) ⟶ C₆H₁₂O₆(aq)
0.01 mol of C₆H₁₂O₆ gives 0.01 mol of solute particles.
NaCl(s) ⟶ Na⁺(aq) + Cl⁻(aq)
1 mol of NaCl gives 0.01 mol of Na⁺(aq) and 0.01 mol of Cl⁻(aq).
That's 0.02 mol of particles, so the freezing point depression of 0.01 mol·L⁻¹ NaCl will be twice that of 0.01 mol·L⁻¹ C₆H₁₂O₆.
Answer:
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive
Explanation:
A wide range of nuclei are found to be NMR active. NMR is the acronym for nuclear magnetic resonance. It is a powerful spectroscopic tool which uses radio waves. The nuclear spin is described by the nuclear quantum number I and can take on values of; 0,1/2, 1, 3/2,2,5/2 etc.
Any nucleus that has an overall spin quantum number of zero (I=0) is NMR inactive e.g Carbon-12 and Oxygen-16 nuclei.
Commonly, all NMR active nuclei posses I ≥ 1/2, Hydrogen -1 , Carbon-13 and boron-11 are common examples of NMR active nuclei.
