Refer to the attachment for answer.

SOME EXTRA INFORMATION:

Bromo is used for Bromine (Br)

Chloro is used for Chlorine(Cl)

'ene' represents double bond between carbon atoms.

'ol' is used for alcohol

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3 years ago

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| A solution containing 4.48 ppm KMnO4 exhibits

Artist 52 [7]

Answer:

Molar absorptivity or molar extinction co-effecient = 2120.14 cm⁻¹M⁻¹

Explanation:

First convert Concentration from ppm inM or mol/l

⇒ Molar mass of KMnO₄ = 158.03 g

⇒ 4.48 ppm = 4.48 mg/l = 4.48 x 10⁻³ g/l

⇒ Molarity = $\frac{4.48 X10^{-3} }{158.03X 1(lit)}$ = 2.83 x 10⁻⁵ molar

Absorbance (A) = - log(T) ( T = % transmittance)

= - log(0.859)

= 0.06

According to Lambert Beer's law

ε = $\frac{A}{C X l}$

or, ε = $\frac{0.06}{2.83 X 10^{-5}X1 cm }$

or, ε = 2120.14 cm⁻¹M⁻¹

Where

ε = Molar absorptivity

A = absorbance

C = Molar concentration of KMnO₄ solution

l = length

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3 years ago