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Harlamova29_29 [7]
3 years ago
10

Calculate the density of the four solutions. All of the solutions has the volume equal to 25 ml. Red solution has 25.0 g of mass

. Green has 26.5 g of mass. Yellow has 28.2 g of mass and Blue one has 30.0 g of mass.
(mark the one best answer)

A.
Red solution density is1.00 g/ml and the blue solution density is 0.83 g/ml

B.
Green solution density is 1.06 g/ml and blue solution density is 1.20 g/ml

C.
Green solution density is 0.94 m=g/ml and yellow solution density is 0.88 g/ml

D.
Blue solution density is 1.00 g/ml and Red solutio density 1.20 g/ml
Chemistry
1 answer:
Scilla [17]3 years ago
3 0

Answer:

              B. Green solution density is 1.06 g/ml and blue solution density is 1.20 g/ml

Explanation:

Density is given as,

                               D = Mass / Volume

Red Solution,

                               D = 25 g / 25 mL

                               D = 1 g/mL

Green Solution,

                               D = 26.5 g / 25 mL

                               D = 1.06 g/mL

Yellow Solution,

                               D = 28.2 g / 25 mL

                               D = 1.128 g/mL

Blue Solution,

                               D = 30 g / 25 mL

                               D = 1.20 g/mL

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4 years ago
What is the percent of nitrogen in dinitrogen pentoxide?
Lostsunrise [7]

Answer: D.) 25.9%

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Calculating the molar mass of N2O5

Atomic mass of nitrogen(N) = 14

Atomic mass of oxygen(O) = 16

Therefore molar mass :

N2O5 = (2 × 14) + (5 × 16) = 28 + 80 = 108g/mol

Percentage amount of elements in N205:

NITROGEN (N) :

(Mass of nitrogen / molar mass of N2O5) × 100%

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3 years ago
In a solution of H2SO4, rank the concentration of H2SO4, H+, SO42- from highest concentration to lowest concentration.
Softa [21]

Answer:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

Explanation:

H₂SO₄ is a strong acid, which means that most of it ionizes in aqueous solution.

Since it is a diprotic acid (two hydrogen ions) its ionization occurs in two steps:

  • H₂SO₄ (aq) → H⁺(aq) + HSO₄⁻(aq)

  • HSO₄⁻ (aq) → H⁺(aq) + SO₄²⁻(aq)

Thus, almost all H₂SO₄ has ionized and its final concentration is almost nothing.

After the first ionization, the conentrations of H⁺(aq) and HSO₄⁻ are equal but by the second ionization more H⁺ ions are produced along with SO₄⁻.

You can show it as one step dissociation, assuming 100% dissociation (given this is a strong acid):

By the stequiometry you can build this table:

                 H₂SO₄ (aq) → 2H⁺(aq) + SO₄²⁻(aq)

Initial                A                 0              0

Change           - x               +2x          +x

Equilibrium       A - x           2x             x

As explained, A - x is very low, and 2x is twice x. Thus,

The rank of the concentrations from highest to lowest is:

  • [H⁺] > [SO₄²⁻] > [H₂SO₄]

5 0
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