All categories

2 years ago

Melanie has 10 packets of 20 biscuits. She puts 3/10 of them on a plate to serve. How many biscuits are being served?

Mathematics

1 answer:

jeka57 [31]2 years ago

4 0

From the problem statement Melanie has 10 packets of 20 biscuits

60 biscuits

Solution

Let us find 3/10 of 10 packets

= 3 packets

In one packet there are 20 biscuits,

Hence in 3 packets there will be

20*3 = 60 biscuits

From the solution above Melanie served 60 biscuits in the plate

Learn more about fraction here:

brainly.com/question/78672

You might be interested in

5. y = (x + 5)2 – 25

Oksana_A [137]

Answer:

Step-by-step explanation:

25+x=25x

25-25=0

y=0

4 0

2 years ago

Which shows the following in order from least to greatest: 85%, 15/18, 0.84 PLEASE HELP

Marrrta [24]

Answer:

15/18, 0.84, 85%

Step-by-step explanation:

Please let me know if you want me to add an explanation as to why this is the answer. I can definitely do that, I just wouldn’t want to write it if you don’t want me to :)

6 0

2 years ago

Read 2 more answers

NEED HELP FAST!

mihalych1998 [28]

The answer is currently A so yep thats the answer ok

8 0

2 years ago

Read 2 more answers

Security A rounds every 2 minutes and 20 seconds in the gate 1. Security B rounds every 1 minute and 40 seconds in the gate 2. I

Elden [556K]

Answer:

$Time = 11\frac{2}{3}\ min$

Step-by-step explanation:

Given

$Security\ A = 2\ mins, 20\ secs$

$Security\ B = 1\ mins, 40\ secs$

Required

After how many minutes, will they round together

First, convert the given time to minutes

$Security\ A = 2\ mins, 20\ secs$

$Security\ A = 2\ mins+ 20\ secs$

$Security\ A = 2\ mins+ \frac{20}{60}\ min$

$Security\ A = 2\ mins+ \frac{1}{3}\ min$

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\ mins, 40\ secs$

$Security\ B = 1\ mins+ 40\ secs$

$Security\ B = 1\ mins+ \frac{40}{60}\ min$

$Security\ B = 1\frac{2}{3}\ min$

So, we have:

$Security\ A = 2\frac{1}{3}\ min$

$Security\ B = 1\frac{2}{3}\ min$

List out the multiples of the time of both security personnel take round.

$Security\ A = 2\frac{1}{3}min,\ 4\frac{2}{3}min,\ 7min,\ 9\frac{1}{3}min,\ 11\frac{2}{3}min...$

$Security\ B = 1\frac{2}{3}min,\ 3\frac{1}{3}min,\ 5min,\ 6\frac{2}{3}min,\ 8\frac{1}{3}min,\ 10min\ ,11\frac{2}{3}min,...$

In the above lists, the common time is:

$Time = 11\frac{2}{3}\ min$

<em>This implies that they go on round after </em> $11\frac{2}{3}\ min$ <em></em>

4 0

2 years ago

What is the shape of the following distribution? {9, 10, 10, 11, 11, 12, 12, 13, 13, 13, 14, 14, 14, 14, 15, 15, 15, 15, 16, 16,

babunello [35]

The shape of the distribution with the following data set you gave is skewed to the left or negatively skewed. This is because the frequency of each number increases as its value increases.

7 0

2 years ago