I think this is true because they’re in the same layer, strata which would mean they died around the same time. Hope this helps sorry if it’s wrong!
Answer:
= 152.40 g
Explanation:
The equation for the reaction is;
Cu(s) + AgNO3 → Ag(s) + Cu(NO3)2
Mass of silver nitrate = 320.0 g × 0.75
= 240.0 g
Molar mass of silver nitrate = 169.87 g/mol
Therefore;
Moles of silver nitrate = 240.0 g/169.87 g/mol
= 1.413 moles
Mole ratio of Silver nitrate to silver metal = 1 : 1
Therefore, moles of silver metal = 1.413 moles
Hence;
Mass of silver metal = 1.413 moles × 107.868 g/mol
<u>= 152.40 g</u>
NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions.
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
Answer:
11 atoms
Explanation:
The formula for lead(II) bicarbonate is: Pb(HCO3)2.
Atoms in Pb(HCO3)2:
Pb=1, H=1×2, C=1×2, O=3×2
1+1×2+1×2+3×2
=1+2+2+6
=11 atoms
A I think let me know if it’s wrong