<u>Answer:</u> The mass of needed is 0.96 grams
<u>Explanation:</u>
To calculate the number of moles, we use the equation:
.....(1)
- <u>For </u><u> :</u>
Given mass of = 320.0 mg = 0.320 g (Conversion factor: 1 g = 1000 mg)
Molar mass of = 20 g/mol
Putting values in equation 1, we get:
For the given chemical equation:
By Stoichiometry of the reaction:
1 mole of is produced from 3 moles of
So, 0.016 moles of will be produced from = of
Now, calculating the mass of from equation 1, we get:
Molar mass of = 20 g/mol
Moles of = 0.048 moles
Putting values in equation 1, we get:
Hence, the mass of needed is 0.96 grams