the final concentration of NaI solution in 60 grams/litre.
Explanation:
Given that:
Initial concentration of NaI solution M1 = 0.2 M
initial volume of NaI V1 = 2 L
Final volume V2 = 1 Litre
Final molarity=?
concentration in grams/litre = ?
molar mass of NaI = 150 gram/mole
For dilution following formula is used:
M1 V1 = M2V2
putting the values in the equation
0.2 X 2 = 1 X M2
M2 = 0.4
For concentration in grams/litre, formula used
molarity = 
mass = 0.4 x 150
= 60 grams
So, 60 grams of NaI will be present in final solution of NaI after evaporation.
The concentration is 60 grams/ L (as volume got reduced to 1 litre from 2 litres)
Answer:
oxidation- reduction
Explanation:
where gaining electronic reduces one element and losing them oxidize the other nitric acid is not only strong it is also a oxidizing agent
<h2>Oxidize: copper = Cu+2</h2>
Answer:
A metalloid is a substance that has both the qualities of a metal and a non metal. Metals conduct electricity and have a high melting point.The element described does not conduct electricity until temperatures are reduced therefore it is not a metal. The fact that conduction occurs when temperatures are reduced means that it is not a non metal because non metals do not conduct electricity at all. Therefore the element is a metaloid because it exhibits some properties of a metal and others of a non mental.
Explanation:
Answer:
1 kilogram weight at sea level would be the equivalent of 2 pounds.
Explanation:
