Answer:
158.004 Grams of Fe2S3
Explanation:
iron(lll) sulfide = Fe2S3 = Molar mass: 207.9 g/mol
iron(lll) bromide = FeBr3 = Molar mass: 295.56 g/mol
Since we don't have the chemical equation we will have to make one I guess.
2 FeBr3 + 3 Na2S -----> 6 NaBr + Fe2S3
449 g iron(lll) bromide = FeBr3
So we have 449/295.56 = moles of FeBr3 = 1.52 Moles
So ratio is 2:1 FeBr3 to Fe2S3
So we need 0.76 moles of Fe2S3
0.76 x 207.9 = 158.004Grams
