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mr Goodwill [35]
3 years ago
14

the high temperature was 28F on friday. The high temperature was -2F on Saturday. What is the differences in these temperature

Mathematics
1 answer:
Gnom [1K]3 years ago
8 0

Answer:

30

Step-by-step explanation:

If you start at -2F and count all the way to 28F you can mark down every count to get your answer.  Or subtract 28F by -2F.

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Line bc is represented by 3x + 2y =8 line ad is a represented by -3 x -2y =6 what is the relationship of line bc to line ad expl
Vlad1618 [11]

Answer:

Parallel lines

Step-by-step explanation:

Line BC:

3x + 2y =8

Line AD:

-3x - 2y =6

Adding both equations, in this case, gives us the point at which the lines intersect:

3x + 2y-3x-2y =8+6\\0=14

Since zero will never equal fourteen, the equation above means that lines BC and AD will never intersect. When two lines have no point in common, they are said to be parallel lines.

8 0
3 years ago
The diameter of a basketball is approximately 24 cm. Find the volume to the nearest
erica [24]

Answer:

b

Step-by-step explanation:

6 0
3 years ago
Kevin Sims bought a car for $12,000. A year is was worth 9,000. What was the percent decrease in value?
morpeh [17]

Answer:

in

Step-by-step explanation:

everybody hates Chris the lottery go exit the bathroom and eat a chicken nugget and and

5 0
3 years ago
Nadia compares the weights, in grams, of some apples and oranges she find the median abs interquartile range of the weights.
choli [55]

Answer:

Apple

Orange

Step-by-step explanation:

Apple has the greater median with a median value of 150 which is more than that of orange at 130

The sample with the greater variability is the orange sample as the interquartile range value of 11 is greater Than 8 for Apple.

Yes it is possible, because of the greater variation on weight shown by the sample of oranges, then it could be possible.

3 0
3 years ago
The circumference of the ellipse approximate. Which equation is the result of solving the formula of the circumference for b?
Serhud [2]

Answer:

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

Step-by-step explanation:

Given - The circumference of the ellipse approximated by C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }where 2a and 2b are the lengths of 2 the axes of the ellipse.

To find - Which equation is the result of solving the formula of the circumference for b ?

Solution -

C = 2\pi \sqrt{\frac{a^{2} + b^{2} }{2} }\\\frac{C}{2\pi }  =  \sqrt{\frac{a^{2} + b^{2} }{2} }

Squaring Both sides, we get

[\frac{C}{2\pi }]^{2}   =  [\sqrt{\frac{a^{2} + b^{2} }{2} }]^{2} \\\frac{C^{2} }{(2\pi)^{2}  }   =  {\frac{a^{2} + b^{2} }{2} }\\2\frac{C^{2} }{4(\pi)^{2}  }   =  {{a^{2} + b^{2} }

\frac{C^{2} }{2(\pi )^{2} }  = a^{2} + b^{2} \\\frac{C^{2} }{2(\pi )^{2} }  -  a^{2} = b^{2} \\\sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}  = b

∴ we get

b = \sqrt{\frac{C^{2} }{2(\pi )^{2} }  -  a^{2}}

8 0
3 years ago
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