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3 years ago

Find the value of x and y so that the quadrilateral is a parallelogram.

Mathematics

1 answer:

Mashutka [201]3 years ago

5 0

Applying the properties of a parallelogram, the values of x and y are: x = 8; y = 20.9

<h3>Properties of a Parallelogram</h3>

The opposite sides in a parallelogram have the same length.
Opposite angles are equal.
Adjacent angles in a parallelogram are supplementary.

4x - 17 = 2x - 1 (equal sides)

Solve for x

4x - 2x = 17 - 1

2x = 16

x = 8

(3y+5) + (6y -13) = 180

Solve for y

9y - 8 = 180

9y = 180 + 8

9y = 188

y = 20.9

Therefore, applying the properties of a parallelogram, the values of x and y are: x = 8; y = 20.9

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Answer:

The answer would be -2.7

Step-by-step explanation:

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3 years ago

(-11x+31y) - 2(-x + 5y)

Cerrena [4.2K]

<u>Answer:</u>

Equivalent expression of (-11x+31y) - 2(-x + 5y) is -9x +21y Hence option C is correct

<u>Solution:</u>

Given expression is (-11x+31y) - 2(-x + 5y)

Need to find equivalent expression from four given option.

Let’s first simplify the given expression

(-11x+31y) - 2(-x + 5y)

On opening the brackets we get

-11x + 31y + 2x -10y

Now bringing similar terms together and performing appropriate operation, we get

-11x + 2x + 31y + -10y

Taking common terms out we get,

=> (-11 + 2) x + (31 -10) y

= -9x +21y

Therefore Equivalent expression of (-11x+31y) - 2(-x + 5y) is -9x +21y.

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3 years ago

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4 years ago

The number of boats B a boat dealer sells in each month of the year from March to December can be modeled by the function B = -1

damaskus [11]

Functions can be used to represent real-life models

The complete table is:

$\mathbf{\left[\begin{array}{ccccccccccccc}{Months}&1&2&3&4&5&6&7&8&9&10&11&12&{Boat\ dealers}&60&75&90&105&120&105&90&75&60&45&30&15\end{array}\right] }$

The function is given as:

$\mathbf{B = -15|t - 5| + 120}$

The value of the function from t = 1 to 12 is as follows:

$\mathbf{B(1) = -15|1 - 5| + 120 = 60}$

$\mathbf{B(2) = -15*|2 - 5| + !20 = 75}$

$\mathbf{B(3) = -15|3- 5| + 120 = 90}$

$\mathbf{B(4) = -15|4- 5| + 120 = 105}$

$\mathbf{B(5) = -15|5- 5| + 120 = 120}$

$\mathbf{B(6) = -15|6- 5| + 120 = 105}$

$\mathbf{B(7) = -15|7- 5| + 120 = 90}$

$\mathbf{B(8) = -15*|8 - 5| + !20 = 75}$

$\mathbf{B(9) = -15|9 - 5| + 120 = 60}$

$\mathbf{B(10) = -15|10 - 5| + 120 = 45}$

$\mathbf{B(11) = -15|11 - 5| + 120 = 30}$

$\mathbf{B(12) = -15|12 - 5| + 120 = 15}$

So, the complete table is:

$\mathbf{\left[\begin{array}{ccccccccccccc}{Months}&1&2&3&4&5&6&7&8&9&10&11&12&{Boat\ dealers}&60&75&90&105&120&105&90&75&60&45&30&15\end{array}\right] }$

See attachment for the function of $\mathbf{B = -15|t - 5| + 120}$

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