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sergij07 [2.7K]
2 years ago
8

1. The perimeter of a rectangle is 30 inches. If its length is three times its width, find both

Mathematics
1 answer:
andrew11 [14]2 years ago
3 0

The length is 11.25 inches.

The width is 3.75 inches.

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Please help me answer this question.
iVinArrow [24]
4 6/9 + 7/9 = 5 3/9
Hope this helps
Answer:
5 3/9 or 5 1/3
3 0
1 year ago
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||BRAINLIEST 20 POINTS!||
Ipatiy [6.2K]

Answer:

-3+1/5

Step-by-step explanation:

4 0
2 years ago
A salesperson earns a commission of $308 for selling $ 2200 in merchandise. Find the commission rate.
Galina-37 [17]

Answer:$247

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5 0
2 years ago
The circumference of a circle is 604 cm. What is the diameter of the circle?
Marta_Voda [28]

Step-by-step explanation:

The Circumference is:

c = 2\pi \: r

Radius r is:

r =  \frac{d}{2}

So,

c = \pi \: d \\ d =  \frac{c}{\pi}  \\ d =  \frac{604}{\pi} \:  cm

6 0
3 years ago
Given the vectors A⃗ and B⃗ shown in the figure ((Figure 1) ), determine the magnitude of B⃗ −A⃗. A is 28 degrees above the posi
Vlad [161]

This problem is represented in the Figure below. So, we can find the components of each vector as follows:


\bullet \ cos(28^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{A_{x}}{44} \\ \\ \therefore A_{x}=44cos(28^{\circ})=38.85m \\ \\ \\ \bullet \ sin(28^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{A_{y}}{44} \\ \\ \therefore A_{y}=44sin(28^{\circ})=20.65m


\bullet \ cos(56^{\circ})=\frac{Adjacent}{Hypotenuse}=\frac{-B_{x}}{26.5} \\ \\ \therefore B_{x}=-26.5cos(56^{\circ})=-14.81m \\ \\ \\ \bullet \ sin(56^{\circ})=\frac{Opposite}{Hypotenuse}=\frac{B_{y}}{26.5} \\ \\ \therefore B_{y}=26.5sin(56^{\circ})=21.97m


Therefore:

\vec{A}=(38.85, 20.65)m \\ \\ \vec{B}=(-14.81, 21.97)m


So:

\vec{B}-\vec{A}=(-14.81, 21.97)-(38.85, 20.65)=(-53.66,1.32)


Finally, the magnitude is:


\boxed{\left| \vec{B}-\vec{A}\right|=\sqrt{(-53.66)^2+(1.32)^2}=53.67m}

7 0
2 years ago
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