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Ipatiy [6.2K]
3 years ago
15

Hiil have some dought​

Mathematics
2 answers:
bonufazy [111]3 years ago
8 0

Answer:

I'm sorry what?

harkovskaia [24]3 years ago
4 0
Ask me, Let’s see if I can help
You might be interested in
Jen earned X dollars on Saturday and Y dollars on Sunday. She plans to save 25% of the money she earned over the weekend and spe
jolli1 [7]
Well 25% is the same as .25 or 1/4. So first you need to add X and Y so X+Y and since it is both you choose D 
5 0
4 years ago
What is X and Y ? Please as fast as you can answer this
olganol [36]

Answer:

28/5=x and y=  -6/5

Step-by-step explanation:

solve by substitution

3x+4y=12

Rewrite equations:

2x+y=10;3x+4y=12

Step1: Solve 2x+y=10 for y:

2x+y=10

2x+y+−2x=10+−2x(Add -2x to both sides)

y=−2x+10

Step2: Substitute−2x+10 for y in 3x+4y=12:

3x+4y=12

3x+4(−2x+10)=12

−5x+40=12(Simplify both sides of the equation)

−5x+40+−40=12+−40(Add -40 to both sides)

−5x=−28

-5x/-5=-28/5

(Divide both sides by -5)

x=  28/5

Step3: Substitute

28/5 for x in "y=−2x+10":

y=−2x+10

y=−2(28/5)+10

y=-6/5(Simplify both sides of the equation)

Hope this helps!

7 0
3 years ago
Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'
aleksandr82 [10.1K]

Answer:

A. △P'Q'R' does not equal △P''Q''R''.

B. Reflecting across UT would change the orientation of the figure.

C. The sequence does not include a reflection that exchanges U and S.

D. Rotating about point U is not a rigid motion because it changes the orientation of the figure.

E. Translating point R' to Q' is a non-invertible transformation because it changes the location of P'.

(D) Rotating about U is not a rigid motion because it changes the orientation of the figure. [I think D is an incorrect answer choice.]

Step-by-step explanation:

Proof No.1

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R' about point U to get △P''Q''R''. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

Proof No.2

Jordan wants to prove △PQR≅△STU using a sequence of rigid motions. This is Jordan's proof. Translate △PQR to get △P'Q'R' with R'=U. Then rotate △P'Q'R about point U to get △P''Q''R'' so that R''Q'' and UT coincide. Since translation and rotation preserve distance, R''Q''=RQ=UT, and Q''=T. Reflect △P''Q''R'' across UT to get △P'''Q'''R''. Since reflection preserves distance, P'''R'''=PR=US, and P'''=S. A sequence of rigid motions maps △PQR onto △STU, so △PQR≅△STU.

8 0
3 years ago
The scale on a road map is
weqwewe [10]
If 1 cm = 500 miles......then 2.2 cm = (2.2 * 500) = 1100 miles <==
8 0
3 years ago
| 2p -1 | =45, what are the values of p?
Alex73 [517]

Answer:

p = 23       and p = -22

Step-by-step explanation:

| 2p -1 | =45

Absolute value equations have 2 solutions, one positive value and one negative

2p-1 = 45    and 2p-1 = -45

Add 1 to all sides

2p-1+1 = 45+1    and 2p-1+1 = -45+1

2p = 46                        2p = -44

Divide by 2

2p/2 = 46/2    and   2p/2  = -44/2

p = 23       and p = -22

5 0
3 years ago
Read 2 more answers
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