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2 years ago

What is the equivalent fraction for 1 3\10

1 answer:

3 0

You can get it as many different ones. The one most likely to be use is 13/10. But here’s a list of equivalent fractions for 1 3/10
13/10 = 26/20 = 39/30
= 52/40 = 65/50 = 78/60
= 91/70 = 104/80 = 117/90
= 130/100 = 143/110 = 156/120
= 169/130 = 182/140 = 195/150
= 208/160 = 221/170 = 234/180
= 247/190 = 260/200 = 273/210
= 286/220 = 299/230 = 312/240
= 325/250 = 338/260 = 351/270
= 364/280 = 377/290 = 390/300
= 403/310 = 416/320 = 429/330
= 442/340 = 455/350 = 468/360
= 481/370 = 494/380 = 507/390
= 520/400 = 533/410 = 546/420
= 559/430 = 572/440 = 585/450
= 598/460 = 611/470 = 624/480
= 637/490 = 650/500 = 663/510
= 676/520 = 689/530 = 702/540
= 715/550 = 728/560 = 741/570
= 754/580 = 767/590 = 780/600
= 793/610 = 806/620 = 819/630
= 832/640 = 845/650 = 858/660
= 871/670 = 884/680 = 897/690
= 910/700 = 923/710 = 936/720
= 949/730 = 962/740 = 975/750
= 988/760 = 1001/770 = 1014/780
= 1027/790 = 1040/800 = 1053/810
= 1066/820 = 1079/830 = 1092/840
= 1105/850 = 1118/860 = 1131/870
= 1144/880 = 1157/890 = 1170/900
= 1183/910 = 1196/920 = 1209/930
= 1222/940 = 1235/950 = 1248/960
= 1261/970 = 1274/980 = 1287/990

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Answer:

Average price, excluding taxes, for each CD is <u>10.20</u>.

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Cost of first 5 CDs, $C_1 = 3.00$

Cost of each additional CD = 15.00

Now, cost of 10 additional CDs is the product of cost of one CD and total number of additional CDs. Therefore,

Cost of 10 additional CDs is, $C_2=15.00\times 10=150.00$

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Total cost of the 15 CDs purchased is given as:

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Now, average price, excluding taxes, for each CD is given as:

$\textrm{Average price}=\frac{\textrm{Total cost of purchase}}{\textrm{Total number of CDs purchased}}\\\\\textrm{Average price}=\frac{C_T}{N}=\frac{153.00}{15}=10.20$

Therefore, the average price, excluding taxes, for each CD is 10.20.

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