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yuradex [85]
2 years ago
6

1.)(-4)^-6(-4)^7 2.)(t^8)^23.)(5t^3)^-4Simplify the expressions?​

Mathematics
1 answer:
statuscvo [17]2 years ago
6 0

Answer:

1.  - 4

2.   t¹⁶

3.   <u>    1      </u>

      625t¹²

Step-by-step explanation:

1.   -4⁻⁶(-4)⁷

-16384/4096 = -4

2.   (t⁸)²

     t¹⁶

3.   (5t³)⁻⁴

<u>    1      </u>

625t¹²

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2018 is the 70th term of the progression.

Explanation
We start out finding the common difference of the progression:
46-17 = 29

Now we write the explicit formula for the sequence.  It is of the form
a_n=a_1+d(n-1)&#10;\\&#10;a_n=17+29(n-1)

We set this equal to 2018 to see if the answer is a whole number.  If it is, it will be the term number that gives us 2018:

2018=17+29(n-1)

Using the distributive property,
2018=17+29*n-29*1
2018=17+29n-29

Combine like terms:
2018=29n-12

Add 12 to both sides:
2018+12=29n-12+12
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8 0
3 years ago
What is four fifths equivalent to
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Step-by-step explanation:

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3 years ago
What is the solution to this system of linear equations?
svetoff [14.1K]
It’s B
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3 years ago
1. Find all the zeros of the polynomial P(x) = 2x^3 – x^2 – 4x+3<br>​
umka21 [38]

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Step-by-step explanation:

4 0
2 years ago
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A map uses a scale of 3/4 in = 80 miles. If two buildings are 60 miles apart in real life, how far apart would they be drawn on
Alla [95]

Given:

The scale of a map is \dfrac{3}{4}\ in=80\ miles.

The distance between two buildings is 60 miles.

To find:

The distance between the given building on the map.

Solution:

We have,

\dfrac{3}{4}\ in=80\ miles

It means, 80 miles in real life = \dfrac{3}{4}\ in on the map.

1 mile in real life = \dfrac{3}{4\times 80}\ in on the map.

60 mile in real life = \dfrac{3\times 60}{4\times 80}\ in on the map.

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Therefore, the buildings are \dfrac{9}{16}\ in apart on the map.

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