28.4% is the answer and that is ur answer
There would be about 1.67 x 10^25 oxygen atoms and about 3.34 x 10^25 hydrogen atoms.
Answer:
Hg∧2+ has a negative standard entropy because the ions are highly solvated in aqueous phase; smaller the ionic size, the more highly it is surrounded by solvated ions. Therefore it will be in highly ordered state hence the entropy decreases.
Hg2 ^2+ has a positive standard entropy because the ionic size of Hg^2+ is smaller than Hg2 ^2+, so therefore the Hg^2+ is highly solvated and that means that it is in highly ordered state. Hg2 ^2+ is not highly solvated so it will have a positive entropy
Explanation:
The values of standard entropy of aqueous ions has a negative standard entropy because the ions are highly solvated in aqueous phase; smaller the ionic size, the more highly it is surrounded by solvated ions. Therefore it will be in highly ordered state hence the entropy decreases.
Hg2 ^2+ has a positive standard entropy because the ionic size of Hg^2+ is smaller than Hg2 ^2+, so therefore the Hg^2+ is highly solvated and that means that it is in highly ordered state. Hg2 ^2+ is not highly solvated so it will have a positive entropy
The advantage of using an orbital notation is that it shows the electron distribution in shells.
<span>Dot structures only show the valence electrons of an atom which are the electrons found at the outermost shell. The orbital notation gives a more detailed depiction of the electrons in each shell. This is most advantageous for atoms that have special cases. </span>
<span>Some examples of atoms that have special electronic configurations are copper and chromium. For example, copper is more stable when the 3d subshell is completely filled. This leaves the 4s subshell with only 1 electron. Chromium is also more stable when its s and d subshells are only half full. The orbital notation depicts these special cases, whereas the dot structure does not.</span>
