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Rudiy27
3 years ago
14

Which is an example of parasitism?

Chemistry
1 answer:
Doss [256]3 years ago
6 0

Answer: A, C, D

Explanation:

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Scrat [10]
When you are tuning an instrument it changes the sound of the instrument
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3 years ago
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Using the formula M1V1 = M2V2 , how many milliliters of a 2. 50 M hydrochloric acid solution is required to make 100. 0 mL of a
gladu [14]

Dilution of the solution can be calculated by the formula of the molarity and volume. The initial volume of 2.50 M solution was 30 mL.

<h3>What is the relationship between molar concentration and dilution?</h3>

Molar concentration or the dilution factor is in an inverse relationship and with an increase in the dilution, the molarity of the solution decreases.

Given,

Initial molarity = 2.50 M

initial volume = ?

Final molarity = 0.750 M

Final volume = 100.0 ml

Substituting values in the formula:

\begin{aligned}\rm V_{1} &= \rm \dfrac{M_{2}V_{2}}{M_{1}}\\\\&= \dfrac{0.750 \times 100}{2.50}\\\\&= 30 \;\rm mL\end{aligned}

Therefore, 30 mL was the initial volume of the solution before it was diluted.

Learn more about dilution here:

brainly.com/question/26896011

3 0
2 years ago
30.5 g of sodium metal reacts with chlorine gas to produce sodium chloride. How much (in grams) chlorine gas must react with thi
Lena [83]

Answer:

Mass of chlorine = 47.22 g

Explanation:

Given data:

Mass of sodium = 30.5 g

Mass of chlorine= ?

Solution:

Chemical equation:

 2Na + Cl₂      →      2NaCl  

Number of moles of Na:

Number of moles = mass/molar mass

Number of moles = 30.5g/ 23 g/mol

Number of moles = 1.33 mol

Now we will compare the moles of Cl ₂ with Na from balance chemical equation.

                    Na            :              Cl ₂

                     2              :               1

                     1.33          :            1/2×1.33 = 0.665 mol

Mass of chlorine gas:

Mass = number of moles × molar mass

Mass = 0.665 mol × 71 g/mol

Mass = 47.22 g

6 0
3 years ago
Help meeee please:) worth 76 pointss
tino4ka555 [31]

Answer:

the particles would not change. solids have definite shape and volume

Explanation:

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3 years ago
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The first step in the reaction of Alka–Seltzer with stomach acid consists of one mole of sodium bicarbonate (NaHCO3) reacting wi
Gnesinka [82]

Answer: 5 moles of  H_2CO_3 can be produced from 5 mol NaHCO3 and 9 mol HCl.

Explanation:

The balanced chemical reaction is:

NaHCO_3+HCl\rightarrow H_2CO_3+NaCl

According to stoichiometry :

1 mole of NaHCO_3 use 1 mole of HCl

Thus 5 moles of NaHCO_3 use=\frac{1}{1}\times 5=5moles  of HCl

Thus NaHCO_3 is the limiting reagent as it limits the formation of product and HCl is the excess reagent.

As 1 mole of NaHCO_3 give = 1 mole of H_2CO_3

Thus 5 moles of NaHCO_3 give =\frac{1}{1}\times 5=5moles  of H_2CO_3

5 moles of  H_2CO_3 can be produced from 5 mol NaHCO_3 and 9 mol HCl.

8 0
3 years ago
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