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Rudiy27
3 years ago
14

Which is an example of parasitism?

Chemistry
1 answer:
Doss [256]3 years ago
6 0

Answer: A, C, D

Explanation:

You might be interested in
CH3OCH3 (ether) will dissolve in water because
dangina [55]

Answer:

a. polar solutes dissolve in polar solvents.

Explanation:

Polarity is a phenomenon that has to do with the positive and negative electric (ionic) charges of a molecule. A molecule with distinct positive and electric charge is said to be POLAR. However, water is said to be a universal solvent because it dissolves more substances than any other solvent can.

This solvent property of water is a function of its POLARITY. Polar solutes dissolve in polar solvents. Hence, only polar solutes can dissolve in water (a polar solvent). Hence, in this case, CH3OCH3 (ether) will dissolve in water because it is a POLAR molecule/solute.

5 0
3 years ago
3.00 L of a gas is collected at 35.0°C and 705.0 mmHg. What is the volume at STP?
makvit [3.9K]

Answer:

2.47L

Explanation:

Using the combined gas law equation as follows:

P1V1/T1= P2V2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

V1 = initial volume (L)

V2 = final volume (L)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question;

P1 = 705mmHg

P2 = 760mmHg (STP)

V1 = 3.00L

V2 = ?

T1 = 35°C = 35 + 273 = 308K

T2 = 273K (STP)

Using P1V1/T1= P2V2/T2

705 × 3/308 = 760 × V2/273

2115/308 = 760V2/273

Cross multiply

308 × 760V2 = 2115 × 273

234,080V2 = 577,395

V2 = 577,395 ÷ 234,080

V2 = 2.47L

8 0
3 years ago
At its critical point, ammonia has a density of 0.235 g cm23. You have a special thick­walled glass tube that has a 10.0­mm outs
salantis [7]

Answer:

\large \boxed{\text{69.3 mg}}

Explanation:

1. Volume of sealed tube

Assume the sealed tube is a right circular cylinder in which the cap and the base are also 4.20 mm thick.

Its outside dimensions are 155 mm long × 10.0 mm diameter.

Its inside dimensions are

h = 155 mm - 2 × 4.20 mm = 146.6 mm

r = 5.0 mm - 4.20 mm = 0.8 mm

V = πr²h = π(0.8)²× 146.6 mm³ = 294.8 mm³ = 0.2948 cm³

2. Calculate the mass of NH₃

\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\\rho & = &\dfrac{m}{V}\\\\0.235 \text{ g$\cdot$ cm}^{-3} & = & \dfrac{m}{\text{0.2948 cm}^{3}}\\\\m & = & \text{0.0693 g}\\& = & \textbf{69.3 mg}\\\end{array}\\\text{You must seal $\large \boxed{\textbf{69.3 mg}}$ of ammonia in the tube.}

4 0
3 years ago
Which elements are solid at room temperature
Kryger [21]

Answer:bromine , neon , helium , argon , lithium , beryllium

Explanation:

8 0
3 years ago
How many moles of dinitrogen monoxide are present in 9.3 x 10^22 molecules of this compound?
Step2247 [10]

Answer:

<h2>0.15 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities.

From the question we have

n =  \frac{9.3 \times  {10}^{22} }{6.02 \times  {10}^{23} }  \\  = 0.154485...

We have the final answer as

<h3>0.15 moles</h3>

Hope this helps you

8 0
3 years ago
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