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Zarrin [17]
3 years ago
15

Choose the correct statement about an atomic nucleus, compared to an atom as a whole. Choose the correct statement about an atom

ic nucleus, compared to an atom as a whole. The nucleus is very tiny but has most of the mass. The nucleus is very tiny and has very little mass. The nucleus is quite large and has most of the mass.
Chemistry
1 answer:
nikitadnepr [17]3 years ago
7 0

<u>Answer:</u> The correct statement is the nucleus is very tiny but has most of the mass.

<u>Explanation:</u>

There are three sub-atomic particles in an atom:

  • <u>Protons:</u> They are positively charged species present in the nucleus of an atom.
  • <u>Electrons:</u> They are positively charged species present around the nucleus of an atom.
  • <u>Neutrons:</u> They are neutral species present in the nucleus of an atom.

Nucleus is defined as the positively charged center of the atom consisting of protons and neutrons. All the mass of atom is contained in the nucleus.

From Rutherford's Gold foil experiment, the nucleus of an atom occupies a very little place.

Hence, the correct statement is the nucleus is very tiny but has most of the mass.

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1.For the reaction P4 O10(s) + 6H2O(l) → 4H3PO4(aq), what mass of P
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P₄O₁₀ + 6H₂O → 4H₃PO₄
The equation shows us that the molar ratio of
P₄O₁₀ : 6H₂O = 1:6

We also know that one mole of a substance contains 6.02 x 10²³ particles. We can use this to calculate the moles of water.
moles(H₂O) = (5.51 x 10²³) / (6.02 x 10²³)
= 0.92 mole
That means moles of P₄O₁₀ = 0.92 / 6
= 0.15

Each mole of P₄O₁₀ contains 4 moles of P. 
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5 0
3 years ago
Read 2 more answers
Consider the following intermediate chemical equations.
QveST [7]

Answer: 250 kJ

Explanation: According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to Hess’s law, the chemical equation can be treated as algebraic expressions and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

P_4(s)+6Cl_2\rightarrow 4PCl_3  \Delta H_1=-2439kJ (1)

4PCl_5(g)\rightarrow P_4(s)+10Cl_2(g)  \Delta H_2=3438kJ (2)

Net chemical equation:

PCl_5(g)\rightarrow PCl_3(g)+Cl_2(g)  \Delta H=? (3)

Adding 1 and 2 we get,

4PCl_5(g)\rightarrow 4PCl_3(g)+4Cl_2 \Delta H_3=\Delta H_1+\Delta H_2=-2439+3438=1000kJ   (4)

Now dividing equation (4) by 4, we get

PCl_5(g)\rightarrow PCl_3(g)+Cl_2

\Delta H=\frac{\Delta H_3}{4}=\frac{1000kJ}{4}=250kJ   (4)

8 0
3 years ago
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