Answer:
21 consonant tiles
Step-by-step explanation:
Henry has a bag containing 39 letter tiles, some consonants, and some vowels.
He selects a tile without looking and then replaces it. If he pulls 7 consonant tiles and 6 vowel tiles, which is the most likely number of consonant tiles in Henry's bag?
Step 1
We add up the number of tiles that he pulls out of the bag
= 7 consonant tiles + 6 vowel tiles
= 13 tiles
Step 2
We divide the total number of tiles in the bag by the total number of tiles that was pulled out of the bag
= 39 tiles ÷ 13 tiles
= 3
Step 3
The most likely number of consonant tiles in Henry's bag is calculated as:
3 × The number of consonant tiles that was pulled out of the bag.
Hence:
3 × 7 consonant tiles
= 21 consonant tiles.
Therefore, the most likely number of consonant tiles in Henry's bag is 21 consonant tiles.
Answer:
500/6 min if I'm correct
Step-by-step explanation:
Answer:
Total number of chairs in the restaurant = 160.
Step-by-step explanation:
Total number of tables in the restaurant = 50
It is given that 40% of the tables have 2 chairs at each table.
40% of 50 = 
= 20
So, 20 tables have 2 chairs at each table.
Number of chairs required for 20 tables = 20 × 2 = 40
Remaining 60% of the tables have 4 chairs at each table.
60% of 50 = 
= 30
So, 30 tables have 4 chairs at each table.
Number of chairs required for 30 tables = 30 × 4 = 120
Hence, total number of chairs in the restaurant = 40 + 120 = 160.
Step-by-step explanation:
sol;
x+1=y...(1)
3y-7=2x....(2)
or, 3(x+1)-72x [from (1)]
or, 3x+3-7=2x
or, 3x-2x=7-3
x=4
now,
putting the value of x in (1)
y=x+1
=4+1
=5
PR and SQ are the diagonal of PQRS.
Answer:
solution given;
let
AB=a
AC=b=30ft
AB=c=20ft
<A=115°
By using Cosine rule.
a²=b²+c²-2bc cos angle
a²=30²+20²-2*30*20 Cos 115°
a²=1807.1419
a=√[1807.1419]
a=42.51
Side A is 42.51ft.
Again
Cos B=
Cos B=
Cos B=0.7687
<B=Cos -¹(0.7687)
<B=39.46°
Angle B is 39.46