Given the equation
which models the data tabulated below:
![\begin{tabular} {|c|c|} x&y\\[1ex] 0.5&10.4\\ 1&5.8\\ 2&3.3\\ 3&2.4\\ 4&2 \end{tabular}](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%0A%7B%7Cc%7Cc%7C%7D%0Ax%26y%5C%5C%5B1ex%5D%0A0.5%2610.4%5C%5C%0A1%265.8%5C%5C%0A2%263.3%5C%5C%0A3%262.4%5C%5C%0A4%262%0A%5Cend%7Btabular%7D)
The linear regression equation is given by
where:
and
We extend the given table as follows:
![\begin{tabular} {|c|c|c|c|} x&y&x^2&xy\\[1ex] 0.5&10.4&0.25&5.2\\ 1&5.8&1&5.8\\ 2&3.3&4&6.6\\ 3&2.4&9&7.2\\ 4&2&16&8\\[1ex] \Sigma x=10.5&\Sigma y=23.9&\Sigma x^2=30.25&\Sigma xy=32.8 \end{tabular} \\ \\ \\ \bar{x}= \frac{\Sigma x}{n} = \frac{10.5}{5} =2.1 \\ \\ \bar{y}=\frac{\Sigma y}{n} = \frac{23.9}{5} =4.78](https://tex.z-dn.net/?f=%5Cbegin%7Btabular%7D%20%7B%7Cc%7Cc%7Cc%7Cc%7C%7D%20x%26y%26x%5E2%26xy%5C%5C%5B1ex%5D%200.5%2610.4%260.25%265.2%5C%5C%201%265.8%261%265.8%5C%5C%202%263.3%264%266.6%5C%5C%203%262.4%269%267.2%5C%5C%204%262%2616%268%5C%5C%5B1ex%5D%20%5CSigma%20x%3D10.5%26%5CSigma%20y%3D23.9%26%5CSigma%20x%5E2%3D30.25%26%5CSigma%20xy%3D32.8%20%5Cend%7Btabular%7D%20%5C%5C%20%5C%5C%20%5C%5C%20%5Cbar%7Bx%7D%3D%20%5Cfrac%7B%5CSigma%20x%7D%7Bn%7D%20%3D%20%5Cfrac%7B10.5%7D%7B5%7D%20%3D2.1%20%5C%5C%20%5C%5C%20%5Cbar%7By%7D%3D%5Cfrac%7B%5CSigma%20y%7D%7Bn%7D%20%3D%20%5Cfrac%7B23.9%7D%7B5%7D%20%3D4.78)
Thus,
and
Therefore, the linearlized form of the equation is y = 9.234 - 2.12x
Part B:
At x = 1.6,
Rearrange
to give
Let
be a variable 'p' and so we can write
as
Rewrite the equation in terms of 'p'
where
using the quadratic formula
and subsitute the value of
There are two value of p; 125 and -27
Now we find the value of x
Earlier we substitute
for
and
for
When
,
![x= \sqrt[3]{125}=5](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B3%5D%7B125%7D%3D5%20)
When
![p = -27, x= \sqrt[3]{-27}=-3](https://tex.z-dn.net/?f=p%20%3D%20-27%2C%20x%3D%20%5Csqrt%5B3%5D%7B-27%7D%3D-3%20)
So the final answer is the two values of x;
x = 5 OR x = -3
Answer:
The CD player's price decreased by 35%
If line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The line AB and BC are intersecting at point B.
Ray BD bisect the angle ABC
∠ABD = x+8 degrees
∠ABD=∠DBC = x+8
Because the ray BD bisect the ∠ABC, so ∠ABD and ∠DBC will be equal
∠ABD+∠DBC= 4x-30 degrees
Because both are vertically opposite angles
Substitute the values in the equation
x+8 + x+8 = 4x-30
2x+16 = 4x-30
2x-4x = -30-16
-2x = -46
x = 23
Hence, if line AB and BC are intersecting at point B and ray BD bisect the angle ABC, then the value of x is 23
The complete question is
Line AB and BC are intersecting at point B and ray BD bisect the angle ABC. What is the value of x?
Learn more about angle here
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