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Ainat [17]
3 years ago
15

Enter the number that belongs in the green box

Mathematics
2 answers:
inn [45]3 years ago
6 0
The answer is 72°, since vertical angles are equal to each other.
rewona [7]3 years ago
3 0

Answer:

72°

Step-by-step explanation:

The diagonals of a parallelogram intersect at a point that forms the center of symmetry of the parallelogram.

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Write an exponential function to describe the given sequence of numbers.
andriy [413]

Answer:

  a(n) = 9·6^(n-1)

Step-by-step explanation:

The general term a(n) of a geometric sequence with first term a(1) and common ratio r is given by ...

  a(n) = a(1)·r^(n-1)

Your sequence has first term 9 and common ratio 54/9 = 6, so the function describing it is ...

  a(n) = 9·6^(n-1)

5 0
3 years ago
-2(9 + 3n) - 9 (1 - 10n)*
GuDViN [60]

Answer:

-27+84n

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Rewrite the radical exponent as a radical
shepuryov [24]
\bf a^{\frac{ n}{ m}} \implies  \sqrt[ m]{a^ n} 
\qquad \qquad
\sqrt[ m]{a^ n}\implies a^{\frac{ n}{ m}}\\\\
-------------------------------\\\\
\left( 5^{\frac{3}{4}} \right)^{\frac{2}{3}}\implies 5^{\frac{3}{4}\cdot \frac{2}{3}}\implies 5^{\frac{1}{2}}\implies \sqrt[2]{5^1}\implies \sqrt{5}
3 0
3 years ago
Rewrite as a simplified fraction 1.6 <-- repeating=?
Norma-Jean [14]
1.6666...=1.\overline{6}=1.(6)\\\\x=1.6666...\ \ \ |multiply\ both\ sides\ by\ 10\\10x=16.6666...\\\\10x-x=16.6666...-1.6666...\\9x=15\ \ \ \ |divide\ both\ sides\ by\ 9\\\\x=\frac{15}{9}\\\\\boxed{x=1\frac{6}{9}}\\\\simplify\\\\x=1\frac{6:3}{9:3}=\boxed{1\frac{2}{3}}
6 0
3 years ago
Line DB bisects ∠ABC, m∠ABD = 4x, and m∠DBC = x + 36. Find m∠ABC. Choose True or False for each statement.
lapo4ka [179]

Since DB bisects ∠ABC and ∠ABC= ∠ABD + ∠DBC, then

∠ABD = ∠DBC, that is

4x = x + 36 ( subtract x from both sides )

3x = 36 ( divide both sides by 3 )

x = 12

∠ABD = 4x = 4× 12 = 48°

∠DBC= x + 36 = 12 + 36 = 48°

∠ABC = 48° + 48° = 96°

Thus statement A is FALSE

statement B is TRUE

statement C is TRUE


4 0
3 years ago
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