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scoundrel [369]
3 years ago
11

Identify the types of motion:-

Physics
1 answer:
miv72 [106K]3 years ago
3 0

Answer:

the movement of snail on the ground is in random motion.

the strings of the guitar is in oscillatory motion.

the whirling of stone tied with a thread is in circular motion.

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What are some of the useful properties of current electricity?
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By definition we have to:

The electric current is the flow of electric charge due to the movement (usually of electrons) that a material travels.

Some properties are:

1) Electric conduction: The conductive materials have a large amount of free electrons, therefore, the passage of electricity is possible.

2) The current inside a circuit is directly proportional to the voltage and inversely proportional to the resistance of the circuit. This is what is known as ohm's law:

I =\frac{V}{R}

3) The current can be continuous or alternate.

Alternating current is the electric current in which the magnitude and direction vary cyclically.

The direct current is the flow of electric charges that does not change direction with time.

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a bucket of water of mass 20kg is pulled at a constant velocity up to a platform 40 meters above the ground. this takes 10 minut
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A slender rod is 90.0 cm long and has mass 0.120 kg. A small 0.0200 kg sphere is welded to one end of the rod, and a small 0.080
deff fn [24]

Answer:

Speed of 0.08 kg mass when it will reach to the bottom position is 1.94 m/s

Explanation:

When rod is released from rest then due to unbalanced torque about the hinge the system will rotate

Now moment of inertia of the system is given as

I = \frac{ML^2}{12} + \frac{m_1L^2}{4} + \frac{m_2L^2}{4}

now we have

M = 0.120 kg

m_1 = 0.02 kg

m_3 = 0.08 kg

now we have

I = \frac{0.120(0.90)^2}{12} + \frac{0.02(0.90)^2}{4} + \frac{0.08(0.90)^2}{4}

so we have

I = 8.1 \times 10^[-3} + 4.05 \times 10^[-3} + 0.0162

I = 0.02835

now by energy conservation we can say work done by gravity must be equal to change in kinetic energy

so we have

\frac{1}{2}I\omega^2 = m_1g \frac{L}{2} - m_2 g\frac{L}{2}

\frac{1}{2}(0.02835)\omega^2 = (0.08 - 0.02)(9.81)(0.45)

\omega = 4.32 rad/s

Now speed of 0.08 kg mass when it reaches to bottom point is given as

v = \omega \frac{L}{2}

v = 4.32 (0.45)

v = 1.94 m/s

3 0
4 years ago
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