Answer:
An elastic collision is a collision in which there is no net loss in kinetic energy in the system as a result of the collision. Both momentum and kinetic energy are conserved quantities inelastic collisions.
Explanation:
Suppose two similar trolleys are traveling toward each other with equal speed. They collide, bouncing off each other with no loss in speed. This collision is perfectly elastic because no energy has been lost. In reality, examples of perfectly elastic collisions are not part of our everyday experience. Some collisions between atoms in gases are examples of perfectly elastic collisions. However, there are some examples of collisions in mechanics where the energy lost can be negligible. These collisions can be considered elastic, even though they are not perfectly elastic. Collisions of rigid billiard balls or the balls in Newton's cradle are two such examples.
Here you go!........ I=1.48A
Answer:
Free body diagram
Explanation:
A free body diagram shows all the forces acting on an object. an example would be a box sitting on the floor.
Draw a square and you would have an arrow from the box pointed down to represent gravity pulling the box down and an arrow from the box pointing upwards to represent the normal force of the ground pushing back. in the scenario the two arrows would be equal length because the forces balance out since the box is motionless. in a situation where there is motion one arrow would be bigger such as if a box was falling. in this example it would have an arrow down to show gravity but no arrow up because it is in free fall. The sum of the forces which is represented by the arrows is what your net force is. The free body diagram helps you visualize all the forces acting on an object.
So based on your question where there is a block of mass m1= 8.8kg in the inclined plane with an angle of 41 with respect to the horizontal. To find the spring constant of the problem were their is a coefficients of friction of 0.39 and 0.429, you must use the formula K*x^2=m*a*sin(angle). By calculating the minimum spring constant is 220.66 N/m^2