If a=-10;then:
a+1=-10+1=-9=b
-9>-10

if a=10; then
a+1=10+1=11=b
11>10
A)The pair of values for a and be are: a=-10, then the value of b would be: -9;
And a=10; then the value of b would be:11;

B) It isn´t possible to create a pair of values for a and be, in wich the numerical relationship shown in the given conditional stament is false, therefore b>a if a+1=b

4 0

3 years ago

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Football fields are 360 ft in length and 160 ft in width. Find the area

rjkz [21]

Answer:

57600cm^2

Step-by-step explanation:

To find the area, you do length * width. In this case, you do 360 * 160. The output will then be 57600cm^2

7 0

2 years ago

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Sin theta+costheta/sintheta -costheta+sintheta-costheta/sintheta+costheta=2sec2/tan2 theta -1

sleet_krkn [62]

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}=\dfrac{2sec^2\theta}{tan^2\theta-1}$

From Left side:

$\dfrac{sin\theta + cos\theta}{sin\theta-cos\theta}\bigg(\dfrac{sin\theta+cos\theta}{sin\theta+cos\theta}\bigg)+\dfrac{sin\theta-cos\theta}{sin\theta+cos\theta}\bigg(\dfrac{sin\theta-cos\theta}{sin\theta-cos\theta}\bigg)$

$\dfrac{sin^2\theta+2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}+\dfrac{sin^2\theta-2cos\thetasin\theta+cos^2\theta}{sin^2\theta-cos^2\theta}$