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Bad White [126]
3 years ago
7

3x^3-2x^2-147x+98=(ax-c)(bx+d)(bx-d) where a,b,c and d positive integers. Work out the value of a,b,c and d

Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Expand the right side:

(ax-c)(bx+d)(bx-d)=(ax-c)(b^2x^2-d^2)

=ab^2x^3-b^2cx^2-ad^2x+cd^2

Notice that 98 = 2 * 7 * 7, so we have c=2 and d=7.

Then

-ad^2=-147\implies a=\dfrac{147}{49}=3

and

ab^2=3\implies b^2=1\implies b=1

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Vinil7 [7]

Answer:

  1. To establish a ratio relation you must see the difference hence 9:4 =2.25
  2. So 2.25, 2.5, 2.11, 3.33, 2.85

From least to greatest:

13:6 ; 9:4 ; 5:2 ; 20:7 ; 10:3

Rate positively and give brainlist

7 0
3 years ago
What is the vertex of f(x)=-x^2-8x
frez [133]

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7 0
3 years ago
Read 2 more answers
Mx+4=3t, solve for x
Dmitriy789 [7]

Answer:

x =3 t /m  -4y/m

Step-by-step explanation:

4 0
3 years ago
Qqqqqqqqqnxkkakakzmmz
Marta_Voda [28]

Answer:

If in rectangular coordinates we have a point (x, y), then the angle defined between the x-axis and a ray that connects the point with the origin is defined by:

Tan(θ) = y/x

Cos(θ) = x/(√(x^2 + y^2))

Sin(θ) = y/(√(x^2 + y^2))

Ctg(θ) = x/y

Sec(θ) = √(x^2 + y^2)/x

Csc(θ) = √(x^2 + y^2)/y

Ok, now we have all the equations.

We know that:

Sec(C) = 30/24

Then:

√(x^2 + y^2) = 30

x = 24

Replacing x in the first equation we get:

√(24^2 + y^2) = 30

y = √(30^2 - 24^2) = 18

Then we have:

x = 24

y = 18

√(x^2 + y^2) = 30

So we can just replace these in the equations:

Tan(C) = y/x = 18/24

Cos(C) = x/(√(x^2 + y^2)) = 24/30

Sin(C) = y/(√(x^2 + y^2)) = 18/30

Ctg(θ) = x/y = 24/18

Sec(θ) = √(x^2 + y^2)/x = 30/24

Csc(θ) = √(x^2 + y^2)/y = 30/18

3 0
3 years ago
Midpoint R(-4,6) and S(2,7)
shusha [124]

To find the midpoint, Add the two X coordinates together then divde by two and then to the same with the Y coordinates:


X = -4 + 2 = -2 / 2 = -1


Y = 6+7 = 13/2


Midpoint = (-1,13/2)



5 0
4 years ago
Read 2 more answers
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