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serious [3.7K]
3 years ago
6

An example of the energy transformation of mechanical energy to electrical energy is

Physics
1 answer:
miskamm [114]3 years ago
4 0

Answer:

generator

Explanation:

motor running to electrical

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A 4kg block is attached to a vertical spring with a spring constant of 800N/m. How much elastic potential energy is stored in th
Marianna [84]

E= \frac{1}{2}×k×x² = 1J

given k=800n/m x=0.05m

7 0
3 years ago
Meaning of power in physics
zmey [24]

Answer:

The rate of doing work is called power.

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3 years ago
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Which statement about cellulose is true?
prohojiy [21]
The correct answer is D
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Use dimensional analysis to determine how the linear acceleration a in m/s2 of a particle traveling in a circle depends on some,
astraxan [27]

I have to say, i love this kind of problems.

So, we got the linear acceleration, as we all know, linear the acceleration its, in dimensional units:

[a]=[\frac{distance}{time^2}].

Now, we got the radius

[r] = [distance]

the angular frequency

[\omega] = \frac{1}{s}

and the mass

[m]=[mass].

Now, the acceleration doesn't have units of mass, so it can't depend on the mass of the particle.

The distance in the acceleration has exponent 1, and so does in the radius. As the radius its the only parameter that has units of distance, this means that the radius must appear with exponent 1. Lets write

a \propto r.

The time in the acceleration has exponent -2 As the angular frequency its the only parameter that has units of time, this means that the angular frequency must appear, but, the angular frequency has an exponent of -1, this means it must be squared

a \propto r \omega^2.

We are almost there. If this were any other problem, we would write:

a = A r \omega^2

where A its an dimensionless constant. Its common for this constants to appears if we need an conversion factor. If we wanted the acceleration in cm/s^2, for example. Luckily for us, the problem states that there is no dimensionless constant involved, so:

a = r \omega^2

5 0
3 years ago
Water is flowing at 4.0 m/s in a circular pipe. If the diameter of the pipe decreases to 1/2 of its former value, what is the ve
Montano1993 [528]

Answer:

v₂ = 16 m/s

Explanation:

We can use the continuity equation, which is as follows:

A_1v_1 = A_2v_2\\

where,

A₁ = Area of inlet = πd²/4

A₂ = Area of outlet = π(d/2)²/4 = πd²/16

v₁ = velocity at inlet = 4 m/s

v₂ = velocity at outlet = ?

Therefore,

(\frac{\pi d^2}{4})(4\ m/s)=(\frac{\pi d^2}{16})v_2\\\\

<u>v₂ = 16 m/s</u>

3 0
3 years ago
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