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3 years ago

15

A 4kg block is attached to a vertical spring with a spring constant of 800N/m. How much elastic potential energy is stored in th

e system?

1 answer:

Marianna [84]3 years ago

7 0

E= $\frac{1}{2}$ ×k×x² = 1J

given k=800n/m x=0.05m

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What is transferred to an object when is done A:energy B:force C:effort D:resistance

liberstina [14]

B force i belive becuase when is done it force

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3 years ago

A horse pulls on an object with a force of 300 newtons and does 12,000 joules of work. How far was the object moved?

liubo4ka [24]

We know, work done = Force * displacement
Here, w = 12,000 J
f = 300 N

Substitute their values into the expression:
12,000 = 300 * d
d = 12,000 / 300
d = 120/3
d = 40 m

In short, Your Answer would be 40 meters

Hope this helps!

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3 years ago

How would a coroner take a body's temperature?

SOVA2 [1]

Answer: Rectal Thermometer

Explanation:

The most common way of taking the temperature of the deceased is to use a rectal thermometer or to take a temperature reading from the liver, which can achieve a more realistic core body temperature. Rigor Mortis also acts as a good measuring stick for estimating the time of death.

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4 years ago

In a mass spectrometer, a single-charged particle (charge e) has a speed of 1.0 × 10 6 m/s and enters a uniform magnetic field o

Nonamiya [84]

Answer:

The mass is $m =6.4*10^{-28} \ kg$

Explanation:

From the question we are told that

The speed of the charge is $v = 1.0 *10^{6} \ m/s$

The magnetic field is $B = 0.20 \ T$

The radius is $r = 0.02 \ m$

The value of the charge is $e = 1.60 *10^{-19} \ C$

The centripetal acting on the charge moving in the circular orbit is mathematically represented as

$F_c = \frac{mv^2}{r }$

Now this centripetal force is due to the force exerted on the charge by the magnetic field on the charge which is mathematically represented as

$F_m = qv B sin\theta$

At the maximum of this magnetic force $\theta = 90 ^o$

So

$F_m = e v B sin(90)$

$F_m = e v B$

Now given that it is this magnetic force that is causing the circular motion we have that

$F_c = F_m$

=> $\frac{mv^2}{r } = ev B$

=> $m = \frac{e * B * r }{v }$

substituting values

$m = \frac{ 1.60 *10^{-19} * 0.20 * 0.020 }{1.0*10^{6} }$

$m =6.4*10^{-28} \ kg$

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4 years ago

In a container which can expand or contract (like a balloon, if the temperature of the gas increases, the volume of that gas ___

Usimov [2.4K]

B. Increases
hope this helps

5 0

4 years ago