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3 years ago

5

A car with a mass of 2,000 kilograms is moving around a circular curve at a uniform velocity of 25 meters per second. The curve

has a radius of 80 meters. What is the centripetal force on the car?
A. 20,250 N
B. 15,625 N
C. 625 N
D. 703 N

1 answer:

34kurt3 years ago

4 0

Formula is. fc = mv^2/r = 2000x25^2/80 ... do the math

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If the mass of an object is 200kg and the applied force is 2600N, calculate the Acceleration.

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Answer:

<em>13 m/s²</em>

Explanation:

Mass of object = 200 Kg

Applied force = 2600 N

Acceleration = ?

Solution:

Definition:

The acceleration is rate of change of velocity of an object with respect to time.

Formula:

a = Δv/Δt

a = acceleration

Δv = change in velocity

Δt = change in time

Units:

The unit of acceleration is m.s⁻².

Acceleration can also be determine through following formula,

F = m × a

a = F/m (N = kgm/s²)

a = 2600 kgm/s² / 200 Kg

a = 13 m/s²

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Imagine a sunny day at the pool. The sun is out and you are thinking about how the light travels from the sun and then hits the

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Answer:

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4 years ago

Read 2 more answers

A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the e

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Answer:

(a) $V_{avg}=2.868m/s$

(b) $V_{avg}=5.352m/s$

(c) $V_{avg}=7.836m/s$

Explanation:

Given data

x(t)=αt²-βt³

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First we need to find distance x at these time so

x(t)=1.53t²-0.0480t³

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at t=2

x(2)=1.53(2)²-0.0480(2)³=5.736m

at t=4s

x(4)=1.53(4)²-0.0480(4)³=21.408 m

For(a) Average velocity at t=0s to t=2s

The average velocity is given as

Vavg=Δx/Δt

$V_{avg}=\frac{x_{f}-x_{i} }{t_{f}-t_{i}}\\ As\\x(0)=0m\\x(2)=5.736m\\V_{avg}=\frac{5.736m-0m }{2s-0s}\\V_{avg}=2.868m/s$

For(b) Average velocity at t=0s to t=4s

The average velocity is given as

Vavg=Δx/Δt

$V_{avg}=\frac{x_{f}-x_{i} }{t_{f}-t_{i}}\\ As\\x(0)=0m\\x(4)=21.408m\\V_{avg}=\frac{21.408m-0m }{4s-0s}\\V_{avg}=5.352m/s$

For(c) Average velocity at t=2s to t=4s

The average velocity is given as

Vavg=Δx/Δt

$V_{avg}=\frac{x_{f}-x_{i} }{t_{f}-t_{i}}\\ As\\x(2)=5.736m\\x(4)=21.408m\\V_{avg}=\frac{21.408m-5.736m }{4s-2s}\\V_{avg}=7.836m/s$

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I would say;

a - bias.

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