AlPO4----> Al+3 + PO4-3
Ksp= [Al+3] x [PO4-3]= 9.84 x 10^-21
Ksp= (x) (x)= x^2
X^2= 9.84x10-21
x= 9.92 x 10^-11
The molar solubility is 9.92 x 10^-11
W=m₁/m₀=2^(-t/T)
t=4.6·10⁹ years
T=5·10¹⁰ years
w=2^(-4.6·10⁹/5·10¹⁰)
w=0.9382
w=93.82%
Answer:
ALL ISOTOPES OF AN ELEMENT HAVE THE SAME NUMBER OF;
1. PROTON
2. ATOMIC NUMBER
Explanation:
Isotopes are atoms with the same atomic number but different mass numbers. Isotopes of an element has the same number of proton which dictates the atomic number of the atoms. The difference in mass number is as a result of the difference in the number of neutrons. Isotopes of an atom have different physical properties but they exhibits the same chemical properties because neutrons have no influence on the chemical properties and the change or difference in neutrons will produce no effect on the chemical properties of the atoms. Neutrons only contributes to the mass of the atoms giving the isotopes of an atom different mass numbers. An example is chlorine with two isotopes, Cl -35 and Cl -37.
Properties Cl-35 Cl-37
mass number 35 37
atomic number 17 17
number of protons 17 17
number of electrons 17 17
number of neutrons 35-17 = 18 37-17 = 20
abundance in nature 75% 25%
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Answer: The concentrations of 
at equilibrium is 0.023 M
Explanation:
Moles of = 
Volume of solution = 1 L
Initial concentration of = 
The given balanced equilibrium reaction is,
Initial conc. 0.14 M 0 M 0M
At eqm. conc. (0.14-x) M (x) M (x) M
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CO]\times [Cl_2]}{[COCl_2]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCO%5D%5Ctimes%20%5BCl_2%5D%7D%7B%5BCOCl_2%5D%7D)
Now put all the given values in this expression, we get :
By solving the term 'x', we get :
x = 0.023 M
Thus, the concentrations of at equilibrium is 0.023 M
