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jasenka [17]
3 years ago
13

The rock outcrop, shown above demonstrates the law of included fragments. Identify the correct definition for the law of include

d fragments.
Any pieces of rock found in another layer are OLDER than the layer in which they are found.

Any pieces of rock found in another layer are YOUNGER than the layer in which they are found.

Any pieces of rock found in another layer are THE SAME AGE as the layer in which they are found.

Any pieces of rock found in another layer are not able to be relative age dated.
100 points if you answer correctly

Chemistry
1 answer:
Radda [10]3 years ago
7 0

Answer:

A

Explanation:

The law of included fragments states: Fragments found in a rock must be older than the rock itself.

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Transformation is into a different type of energy Ex: chemical to physical

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Explanation:

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I need help with this one
Kruka [31]

Answer:

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3 years ago
A scientist measures the standard enthalpy change for the following reaction to be -17.2 kJ : Ca(OH)2(aq) 2 HCl(aq)CaCl2(s)
elixir [45]

Answer: \Delta H^{0}=-173.72 kJ/mol

Explanation: <u>Enthalpy</u> <u>Change</u> is the amount of energy in a reaction - absorption or release - at a constant pressure. So, <u>Standard</u> <u>Enthalpy</u> <u>of</u> <u>Formation</u> is how much energy is necessary to form a substance.

The standard enthalpy of formation of HCl is calculated as:

\Delta ^{0}=\Sigma H_{products}-\Sigma H_{reactants}

Ca(OH)_{2}_{(aq)}+2HCl_{(aq)} → CaCl_{2}_{(s)}+2H_{2}O_{(l)}

Standard Enthalpy of formation for the other compounds are:

Calcium Hydroxide: \Delta H^{0}= -1002.82 kJ/mol

Calcium chloride: \Delta H^{0}= -795.8 kJ/mol

Water: \Delta H^{0}= -285.83 kJ/mol

Enthalpy is given per mol, which means we have to multiply by the mols in the balanced equation.

Calculating:

-17.2=[-795.8+2(285.85)]-[-1002.82+2\Delta H]

-17.2=-1367.46+1002.82-2\Delta H

2\Delta H=17.2-364.64

\Delta H=-173.72

So, the standard enthalpy of formation of HCl is -173.72 kJ/mol

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3 years ago
BRAINLIEST ANSWER! An Earth-like planet is 500 light years away. Why is this an obstacle for a manned space mission?
Over [174]
C sounds correct........
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I need help, I don't understand the question
Oduvanchick [21]
Remember this. 

Ionic molecules has ionic bonds
Nonpolar molecules has dispersion (Van del Waals)
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a. polar- dipole-dipole
b. polar- hydrogen bonding
c. nonpolar- dispersion
d. nonpolar- dispersion
e. polar- dipole-dipole
f. polar-dipole-dipole
g. nonpolar- dispersion
h. polar- hydrogen bonding.
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4 years ago
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