Iodine..............................
Balanced equation is
HBr + NaOH ----> NaBr + H2O
Using molar masses
80.912 g HBr reacts with 39.997 g of Naoh to give 18.007 g water
so 1 gram of NaOH reacts with 2.023 g of HBR
and 5.7 reacts with 11.531 g HBr so we have excess HBr in this reaction
Mass of water produced = (5.7 * 18.007 / 39.997 = 2.6 g to 2 sig figs
Answer:
5.64×10²³ atoms C
Explanation:
Convert moles of H to moles of C:
2.81 mol H × (2 mol C / 6 mol H) = 0.937 mol C
Convert moles of C to atoms of C:
0.937 mol C × (6.02×10²³ atoms C / mol C) = 5.64×10²³ atoms C
<u>Answer:</u> The temperature will be 1501.47 K.
<u>Explanation:</u>
To calculate the temperature of the gas when pressure is increased, we use the equation given by Gay-Lussac's Law.
This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.
Mathematically,
or,
where,
are the initial pressure and initial temperature of the gas.
are the final pressure and final temperature of the gas.
We are given:
Putting values in above equation, we get:
Hence, the temperature will be 1501.47 K
1. 80 Kj
2. 120-80= 40 Kj
3. 120-20= 100Kj
4. 20-80= -60Kj
5. +60 Kj
6. Exothermic because 4 is negative
