Lewis structures refers to the diagrams used to signify the bonding between the atoms of a molecule and the lone pair of electrons, which may prevail in the molecule. These structures are drawn on the basis of the formal charge of each atom within the ion or molecule.
The formal charge refers to the charge assigned to an atom in a molecule, which all the electrons are shared equivalently amongst the atoms regardless of its electronegativity.
The rule for formal charge calculation is,
Formal charge = no of valency shell electron - 1/2 of the no of shared pair electron - no of lone pair electron.
So, in this case, the formal charge of P = 5 - 1/2 (10) - 0 = 0
The valence shell of P have 5 electrons. The total 5 bond is there in the given composition, so total 10 bonding electron, and there is no lone pair of electron on P atom. So, formal charge of P is 0.
Answer:
a). The energy released by the alpha decay of 222 Rn is to 218 Po :
= 5.596 MeV
b).The energy of the alpha particle is 5.5 MeV
c) The recoil energy of Po = 0.096 MeV
Explanation:
The equation for the alpha decay of Rn to Polonium is:
The energy of the decay process can be calculated using:
= Change in the mass
Mass of Po = 218.008965 u
Mass of He = 4.002603 u
Mass of Rn = 222.017576 u
= mass of Po + mass of He - mass of Rn
= 4.002603 + 218.008965-222.017576
= - 0.006008
= -5.596 MeV
<u><em>The negative sign means energy is released during the process.</em></u>
b) The energy of the alpha particle is :
= 5.494 MeV
= 5.5 MeV
c).
Recoil energy: When the parent nucleus is at rest before the decay then , there must be the some recoil of daughter nucleus to conserve the momentum.This is termed as recoil energy.
<u><em>The energy of the recoil polonium atom :</em></u>
The formula for recoil energy is :
<em>The total energy - the kinetic energy</em>
<em>= 5.596 - 5.5 </em>
<em>= 0.096 MeV</em>
They tell you to have caution.
I don’t know if this works
Answer:
<h2>1.11 g/mL</h2>
Explanation:
The density of a substance can be found by using the formula
From the question we have
We have the final answer as
<h3>1.11 g/mL</h3>
Hope this helps you
