Answer is: <span>D)194 kJ/mol, exothermic
</span>ΔHreaction = ∑(product bond energies) - ∑(reactant bond energies).
∑(product bond energies) = ΔHreaction + ∑(reactant bond energies).
ΔHreaction must be negative (exothermic) if ∑(product bond energies) is positive.
∑(product bond energies) = -1352 kJ/mol + <span>1546 kJ/mol.
</span>∑(product bond energies) = 194 kJ/mol.
∑ is summation.
You want to divide by avagadros number (6.22 x 10^23). This will cancel the atoms unit and give moles, moles of Iridium. Now you want to calculate the atomic mass of Iridium which is in units of grams per mole. Multiply these two numbers and the moles will cancel giving you grams.
Setting up a dimension analysis type of thing helps tremendously. See what you have to cancel in order to get what you want. We canceled the atoms, then we canceled the moles, and then we got grams.
Answer:
pOH = 13.246
Explanation:
pH = -log[H+]
[H+] = [HBr] porque HBr es un acido fuerte.
pH = -log(0.176) = 0.754
pH + pOH = 14
pOH = 14 - 0.754 = 13.246
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