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allsm [11]
3 years ago
5

PLEASE SHOW FULL SOLUTIONS!!! WILL MARK BRAINLIEST FOR BEST ANSWER!!

Mathematics
2 answers:
mestny [16]3 years ago
8 0

This is my answer. Check it!

<em>A</em><em>n</em><em>s</em><em>w</em><em>e</em><em>r</em><em>e</em><em>d</em><em> </em><em>b</em><em>y</em><em> </em><em>B</em><em>e</em><em>n</em><em>j</em><em>e</em><em>m</em><em>i</em><em>n</em>

mylen [45]3 years ago
7 0

Answer:

  • See below

Step-by-step explanation:

<u>Let us have:</u>

  • a - the first term
  • r - common ratio
  • l - the last term

<u>Formula of nth or last term:</u>

  • l = arⁿ⁻¹

<u>The sequence:</u>

  • a, ar, ar², ..., arⁿ⁻¹

<u>The sum of the sequence is:</u>

  • S = a + ar + ar² + ... + arⁿ⁻¹

<u>Lets multiply the sum by r and subtract the sum:</u>

  • rS = ar + ar² + ar³ + ... + arⁿ
  • S = a + ar + ar² + ... + arⁿ⁻¹
  • rS - S = arⁿ - a = r(arⁿ⁻¹) - a = lr - a

<u>Solve this for S:</u>

  • S(r - 1) = lr - a
  • S = (lr - a)/(r - 1)

So we have a sum formula determined by the first, last terms and the common ratio.

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