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jekas [21]
2 years ago
7

Events d and e are independent, with p( d ) = 0. 6 and p( d and e ) = 0. 18. Which of the following is true?.

SAT
1 answer:
balu736 [363]2 years ago
3 0

Answer:

(D) P(D or E) = 0.72

Explanation:

That's the correct answer.

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my mind went... "BOOM!*

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2 years ago
To compare the average amount of time that canadians and americans spend commuting, a researcher collects a sample of canadians
yKpoI14uk [10]

The standard error of the difference of sample means is 0.444

From the complete question, we have the following parameters

<u>Canadians</u>

  • Sample size = 50
  • Mean = 4.6
  • Standard deviation = 2.9

<u>Americans</u>

  • Sample size = 60
  • Mean = 5.2
  • Standard deviation = 1.3

The standard error of a sample is the quotient of the standard deviation and the square root of the sample size.

This is represented as:

SE = \frac{\sigma}{\sqrt n}

The standard error of the Canadian sample is:

SE_1 = \frac{2.9}{\sqrt{50}}

So, we have:

SE_1 = 0.41

The standard error of the American sample is:

SE_2 = \frac{1.3}{\sqrt{60}}

So, we have:

SE_2 = 0.17

The standard error of the difference of sample means is then calculated as:

SE= \sqrt{SE_1^2 + SE_2^2}

This gives

SE= \sqrt{0.41^2 + 0.17^2}

SE= \sqrt{0.197}

Take square roots

SE= 0.444

Hence, the standard error of the difference of sample means is 0.444

Read more about standard errors at:

brainly.com/question/6851971

5 0
2 years ago
Can anyone thank you for me plz plz plz​
serg [7]

Answer:

first what is the question

3 0
3 years ago
Read 2 more answers
The point (−2,4) lies on the curve in the xy-plane given by the equation f(x)g(y)=17−x−y, where f is a differentiable function o
Nikitich [7]

The value of \frac{dy}{dx} is -3. \blacksquare

<h2>Procedure - Differentiability</h2><h3 /><h3>Chain rule and derivatives</h3><h3 />

We derive an expression for \frac{dy}{dx} by means of chain rule and differentiation rule for a product of functions:

\frac{d}{dx}[f(x)\cdot g(y)] = [f'(x)\cdot \frac{dx}{dx}]\cdot g(y) + f(x) \cdot [g'(y)\cdot \frac{dy}{dx} ]

\frac{d}{dx}[f(x)\cdot g(y)] = f'(x)\cdot g(y) +f(x)\cdot g'(y)\cdot \frac{dy}{dx} (1)

If we know that f(x) \cdot g(y) = 17-x-y, f(-2) = 3,<em> </em>f'(-2) = 4,<em> </em>g(4) = 5 andg'(4) = 2, then we have the following expression:

-1-\frac{dy}{dx} = (4)\cdot (5) + (3)\cdot (2) \cdot \frac{dy}{dx}

-1-\frac{dy}{dx} = 20 + 6\cdot \frac{dy}{dx}

7\cdot \frac{dy}{dx} = -21

\frac{dy}{dx} = -3

The value of \frac{dy}{dx} is -3. \blacksquare

To learn more on differentiability, we kindly invite to check this verified question: brainly.com/question/24062595

<h3>Remark</h3>

The statement is incomplete and full of mistakes. Complete and corrected form is presented below:

<em>The point (-2, 4) lies on the curve in the xy-plane given by the equation </em>f(x)\cdot g(y) = 17 - x\cdot y<em>, where </em>f<em> is a differentiable function of </em>x<em> and </em>g<em> is a differentiable function of </em>y<em>. Selected values of </em>f<em>, </em>f'<em>, </em>g<em> and </em>g'<em> are given below: </em>f(-2) = 3<em>, </em>f'(-2) = 4<em>, </em>g(4) = 5<em>, </em>g'(4) = 2<em>. </em>

<em />

<em>What is the value of </em>\frac{dy}{dx}<em> at the point </em>(-2, 4)<em>?</em>

3 0
2 years ago
What is the claim? exercise and diet help people lose more weight than with the aid of this drug. This drug helps people lose mo
sdas [7]

Answer:

This drug helps people lose more weight than diet and exercise alone. The reason for this statement is that with diet and exercise alone, 23% lost weight whereas with diet, exercise and the drug, 48% lost weight so the conclusion is that the drug enhanced weight loss.

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2 years ago
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