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klemol [59]
3 years ago
14

In a 5/6 pound mixture of sand and gravel, 1/4 pound is gravel.

Mathematics
2 answers:
USPshnik [31]3 years ago
8 0
<span>Total mass of mixture is given as 5/6 pound, in which 1/4 pound is gravel. Amount of sand in the mixture will be 5/6 - 1/4 = 7/12 So, the ratio of sand to that of gravel in given mixture is 7/12:1/4 = 7:3. i.e every 10 parts of mixture contain 7 parts of sand and 3 parts of gravel. If we are given 1-pound of same mixture, it will contain 1 * 3/10 pound gravel, i.e. 0.3 pound.</span>
Nataliya [291]3 years ago
3 0
1/4lbs of gravel is in 5/6lbs of mixture
xlbs of gravel is in 1lbs of mixture
1/4:5/6=x:1, 1/4*1=5/6*x
5/6*x=1/4, x=(1/4)/(5/6)
x=3/10
In 1 pound of mixture of sand and gravel, 3/10 pound is gravel.

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Write one sine and one cosine equation for each graph below.
pychu [463]

Answer:

Q13. y = sin(2x – π/2); y = - 2cos2x  

Q14. y = 2sin2x -1; y = -2cos(2x – π/2) -1

Step-by-step explanation:

Question 13

(A) Sine function

y = a sin[b(x - h)] + k

y = a sin(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Phase shift = π/2.  

2h =π/2

h = π/4

The equation is

y = sin[2(x – π/4)} or

y = sin(2x – π/2)

B. Cosine function

y = a cos[b(x - h)] + k

y = a cos(bx - bh) + k; bh = phase shift

(1) Amp = 1; a = 1

(2) The graph is symmetrical about the x-axis. k = 0.

(3) Per = π. b = 2

(4) Reflected across x-axis, y ⟶ -y

The equation is y = - 2cos2x  

Question 14

(A) Sine function

(1) Amp = 2; a = 2

(2) Shifted down 1; k = -1

(3) Per = π; b = 2

(4) Phase shift = 0; h = 0

The equation is y = 2sin2x -1

(B) Cosine function

a = 2, b = -1; b = 2

Phase shift = π/2; h = π/4

The equation is

y = -2cos[2(x – π/4)] – 1 or

y = -2cos(2x – π/2) - 1

6 0
3 years ago
How can you solve problems involving direct variation?
never [62]

Answer:

Solving a Direct Variation Problem

Write the variation equation: y = kx or k = y/x.

Substitute in for the given values and find the value of k.

Rewrite the variation equation: y = kx with the known value of k.

Substitute the remaining values and find the unknown.

Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

8 0
3 years ago
Pls help I don’t get it
Setler [38]

Answer:

x=-5, y=-2

Step-by-step explanation:

10x-9y=-32

2x-10y=10

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(10x-9y)-(10x-50y)=-32-50

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3 0
2 years ago
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