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3 years ago

7

Itemized Charitable Contributions The average charitable contribution itemized per income tax return in Pennsylvania is $792. Su

ppose that
the distribution of contributions is normal with a standard deviation of $108. Find the limits for the middle 58% of contributions.

1 answer:

aliina [53]3 years ago

6 0

Answer:

B

Step-by-step explanation:

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Two similar prisms are in a ratio of 5:6. What is the ratio of their volumes?

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Answer:

Sorry sis don't know the answer

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3 years ago

Please solve thank you if so

cupoosta [38]

Answer:

5(3) + i = 30

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Step-by-step explanation:

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3 years ago

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The perimeter of a rectangular garden used 86 feet of barbed wire. The length of the garden is 7 feet more than its width. Find

Taya2010 [7]

Answer:

Step-by-step explanation:

perimeter of a rectangle = twice the length plus twice the width

P = 2L + 2W equation 1 P = 86 ft

Given the length is seven feet more than the width

L = W + 7 equation 2

Substitute equation 2 into equation 1

P = 2(W+7) + 2W = 86 ft

2W +14 + 2W = 86 ft

4W = 86 - 14

W = 72 / 4

W = 18 feet

6 0

3 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) <em>To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the</em><em> critical points.</em>

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

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3 years ago

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One piece is 8ft and the other is 19ft

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4 years ago

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