The position of the kite with the point directly beneath the kite at the same
level with the hand and the hand for a right triangle.
- The height of the kite above the is approximately <u>66.314 feet</u>.
Reasons:
The height of his hands above the ground, h = 2.75 feet
Angle of elevation of the string (above the horizontal), θ = 26°
Length of the string, <em>l</em> = 145 feet
Required:
The height of the kite above the ground.
Solution:
The height of the kite above the ground is given by trigonometric ratios as follows;
![\displaystyle Height \ of \ kite, \, k_h = \mathbf{h + l \times sin(\theta)}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Height%20%5C%20of%20%5C%20kite%2C%20%5C%2C%20k_h%20%3D%20%5Cmathbf%7Bh%20%2B%20l%20%5Ctimes%20sin%28%5Ctheta%29%7D)
Therefore;
![\displaystyle Height \ of \ kite, \, k_h = 2.75 + 145 \times sin(26^{\circ}) \approx \mathbf{66.314}](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Height%20%5C%20of%20%5C%20kite%2C%20%5C%2C%20k_h%20%3D%202.75%20%2B%20145%20%5Ctimes%20sin%2826%5E%7B%5Ccirc%7D%29%20%5Capprox%20%5Cmathbf%7B66.314%7D)
The height of the kite above the,
≈ <u>66.314 feet</u>
Learn more about trigonometric ratios here:
brainly.com/question/9085166